在php中仅使用for循环的反向字符串
如果有一个阵列:在php中仅使用for循环的反向字符串,php,arrays,Php,Arrays,如果有一个阵列: $arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w'); 我想在php中使用for loop only显示输出,如1st string=revo和2nd string=flow。不要使用任何内置的php函数 那我怎么做呢?请帮助我。解决方案是: $arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w'); |_________________| |_______
$arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w');
我想在php中使用for loop only显示输出,如1st string=revo
和2nd string=flow
。不要使用任何内置的php函数
那我怎么做呢?请帮助我。解决方案是:
$arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w');
|_________________| |_________________|
^ ^
Reverse this half Keep this half as it is
然后在数组中循环创建第一个和第二个字符串
$arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w');
// Reverse the first half of the array
$arrLength = count($arr);
for($i = 0; $i < $arrLength / 4; ++$i){
$tmp = $arr[$i];
$arr[$i] = $arr[(($arrLength / 2) - 1) - $i];
$arr[(($arrLength / 2) - 1) - $i] = $tmp;
}
// Loop through the array to create first and second string
$firstString = $secondString = "";
for($i = 0; $i < $arrLength; ++$i){
if($i < $arrLength / 2){
$firstString .= $arr[$i];
}else{
$secondString .= $arr[$i];
}
}
echo "First String: " . $firstString . "<br />";
echo "Second String: " . $secondString . "<br />";
试试这个
<?php
$arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w');
$str1='';
$str2 ='';
//where we gave for loop length as 8(arr length)
for($i = 0; $i <8; $i++) {
if($i<4){ //which is used to reverse the first half string
$j =3;
$str1.=$arr[$j-$i];
//where we reverse the order as 3,2,1,0.and concat the each char as string.
}else{
$str2 .= $arr[$i];
//rest char is simply passed as string 2
}
}
echo $str1."</br>";
echo $str2;
?>
如何告诉在哪里分割输入?只需将数据分成大小相同的两部分?数组是否总是包含偶数个字符?如果有一个数组包含奇数个字符怎么办?为什么有人要尝试这个?一个好的答案解释了所做的更改以及更改的原因。
<?php
$arr = array('o', 'v', 'e', 'r','f', 'l', 'o', 'w');
$str1='';
$str2 ='';
//where we gave for loop length as 8(arr length)
for($i = 0; $i <8; $i++) {
if($i<4){ //which is used to reverse the first half string
$j =3;
$str1.=$arr[$j-$i];
//where we reverse the order as 3,2,1,0.and concat the each char as string.
}else{
$str2 .= $arr[$i];
//rest char is simply passed as string 2
}
}
echo $str1."</br>";
echo $str2;
?>