表单操作在php类函数中不起作用

我在

class\u promotions.php中有班级促销活动

class Promotion{ 

  function promotionForm(){ 

     <form method="post" action="  admin_panel.php?admin=admin-pro&admin=addpro   ">         
        Title: <input type="text" name="title" />        
        Description: <input type="text" name="des" />        
        <input type="submit" name="title" />     

     </form> 

  }    

  //and the 2nd function in same class is     
  function insertPromotions(){     
    //this function will get the val from admin_panel.php page and insert val to database
  }    

}    

"admin_panel.php?title=field-val&des=field-val" 

"admin_panel.php?admin=admin-pro&admin=addpro&title=field-val&des=field-val"

但我需要在提交表格的链接是这样的

"admin_panel.php?title=field-val&des=field-val" 

"admin_panel.php?admin=admin-pro&admin=addpro&title=field-val&des=field-val"

如何在提交表单后从特定功能中获取该链接
您可以像这样使用
隐藏
：

"admin_panel.php?title=field-val&des=field-val" 

"admin_panel.php?admin=admin-pro&admin=addpro&title=field-val&des=field-val"

<form method="get" action="admin_panel.php">
<input type="hidden" name="admin" value="admin-pro"> 
<input type="hidden" name="foo" value="bar"> 

希望这有助于
I+1，但我认为您应该链接到

"admin_panel.php?title=field-val&des=field-val" 

"admin_panel.php?admin=admin-pro&admin=addpro&title=field-val&des=field-val"