如何使用Ajax将表单数据传递到PHP，并使用jQuery显示错误消息，而无需页面刷新

我有一个带文件上传器的表格。我想在不刷新页面的情况下显示错误消息。我想我需要用jQuery显示错误，并用Ajax将文件传递给PHP脚本。我不知道该怎么做

这是我当前的代码。提交后，它会将您重定向到

upload.php

，并在那里显示错误/成功消息，但它对用户不是很友好

<form method="post" action="upload.php" enctype="multipart/form-data">
     <div id="file_upload">
          <input type="file" name="file">
          <input type="submit" value="Upload">
     </div>
</form>


<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["file"]["name"]);
$uploadOk = 1;
$fileType = pathinfo($target_file,PATHINFO_EXTENSION);

// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists. Rename and try again.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["file"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($fileType != "zip" ) {
    echo "Sorry, only zip files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["file"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>

---

您可以将Ajax与

FormData（）一起使用。

：

下面是我们的HTML代码：

<form method="post" onsubmit="return submitForm()" action="upload.php" enctype="multipart/form-data">
     <div id="file_upload">
          <input type="file" name="file">
          <input type="submit" value="Upload">
     </div>
</form>

---

您可以将Ajax与

FormData（）

一起使用：

下面是我们的HTML代码：

<form method="post" onsubmit="return submitForm()" action="upload.php" enctype="multipart/form-data">
     <div id="file_upload">
          <input type="file" name="file">
          <input type="submit" value="Upload">
     </div>
</form>

---

在这里，您可以使用此代码。它会帮助你的

Html

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post" action="upload.php" enctype="multipart/form-data" class="upload_form">
 <div id="file_upload">
      <input type="file" name="file">
      <input type="submit" value="Upload">
 </div>
</form>

PHP

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["file"]["name"]);
$uploadOk = 1;
$fileType = pathinfo($target_file,PATHINFO_EXTENSION);

// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists. Rename and try again.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["file"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($fileType != "zip" ) {
    echo "Sorry, only zip files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["file"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>

---

在这里，您可以使用此代码。它会帮助你的

Html

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post" action="upload.php" enctype="multipart/form-data" class="upload_form">
 <div id="file_upload">
      <input type="file" name="file">
      <input type="submit" value="Upload">
 </div>
</form>

PHP

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["file"]["name"]);
$uploadOk = 1;
$fileType = pathinfo($target_file,PATHINFO_EXTENSION);

// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists. Rename and try again.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["file"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($fileType != "zip" ) {
    echo "Sorry, only zip files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["file"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>

---

根据您的代码尝试此选项

HTML

和

Script

File
添加letest.js库：

---

按照你的代码试试这个

HTML

和

Script

File
添加letest.js库：

使用jquery

ajax（）

和

FormData

上传文件并获得响应。使用jquery

ajax（）

和

FormData

上传文件并获得响应。

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES['file-0']['name']);
$uploadOk = 1;
$fileType = pathinfo($target_file,PATHINFO_EXTENSION);

//echo $target_file;/*
// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists. Rename and try again.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["file-0"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($fileType != "zip" ) {
    echo "Sorry, only zip files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["file-0"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["file-0"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}
?>