Php Yii中是否有超过两个级别的with（）？

我正在尝试这样做：

$this->PickTicketLineModel->PickTicket->SO->CustomerShipToModel

如果我仔细检查每一件作品，我会得到一个用于PickTicketLine的模型，一个用于PickTicket，一个用于SO。当我到达CustomerShipToModel时，我返回null。因为这应该与数据库中的现有行匹配，所以我假设关系出现了问题。有什么建议吗

选择票证行表关系

'PickTicket' => array(self::BELONGS_TO, 'TblwhPickTicket', 'PickTicketNumber'),

'SO' => array(self::BELONGS_TO, 'TblsoSO', 'SONumber'),

'CustomerShipToModel' => array(self::BELONGS_TO, 'TblarCustomerShipTo', 'CustomerShipTo'),

'CustomerShipToModel' => array(self::HAS_MANY, 'TblarsoSO', 'CustomerShipTo'),

选择票证表关系

'PickTicket' => array(self::BELONGS_TO, 'TblwhPickTicket', 'PickTicketNumber'),

'SO' => array(self::BELONGS_TO, 'TblsoSO', 'SONumber'),

'CustomerShipToModel' => array(self::BELONGS_TO, 'TblarCustomerShipTo', 'CustomerShipTo'),

'CustomerShipToModel' => array(self::HAS_MANY, 'TblarsoSO', 'CustomerShipTo'),

那么表关系呢

'PickTicket' => array(self::BELONGS_TO, 'TblwhPickTicket', 'PickTicketNumber'),

'SO' => array(self::BELONGS_TO, 'TblsoSO', 'SONumber'),

'CustomerShipToModel' => array(self::BELONGS_TO, 'TblarCustomerShipTo', 'CustomerShipTo'),

'CustomerShipToModel' => array(self::HAS_MANY, 'TblarsoSO', 'CustomerShipTo'),

客户发货到表的关系

'PickTicket' => array(self::BELONGS_TO, 'TblwhPickTicket', 'PickTicketNumber'),

'SO' => array(self::BELONGS_TO, 'TblsoSO', 'SONumber'),

'CustomerShipToModel' => array(self::BELONGS_TO, 'TblarCustomerShipTo', 'CustomerShipTo'),

'CustomerShipToModel' => array(self::HAS_MANY, 'TblarsoSO', 'CustomerShipTo'),

这就是我最初获得PickTicketLine模型的原因：

$this->pickTicketLine = TblwhPickTicketLine::model()->with('PickTicket','PickTicket.SO')->FindByPk(array('PickTicketNumber'=>$pickTicketNumber, 'PickTicketLineNumber'=>$pickTicketLineNumber));

---

尝试显式加载所有相关数据：

$this->pickTicketLine = TblwhPickTicketLine::model()->with(array(
    'PickTicket' => array(
        'with' => array(
            'SO' => array(
                'with' => array('CustomerShipToModel')
            )
        )
    )        
))->findByPk(array(
    'PickTicketNumber'=>$pickTicketNumber,
    'PickTicketLineNumber'=>$pickTicketLineNumber
));

如果这也不起作用，请记录数据库请求并检查查询，如Pentium10在注释中所建议的那样。您可以让phpMyAdmin执行查询，或者使用MySQL“EXPLAIN”关键字获取更多信息。为了获取相关日志，必须将以下行添加到config/main.php文件中：

'components'=>array(
    'db'=>array(
        'enableProfiling' => true,
        'enableParamLogging' => true
    )
)

---

尝试显式加载所有相关数据：

$this->pickTicketLine = TblwhPickTicketLine::model()->with(array(
    'PickTicket' => array(
        'with' => array(
            'SO' => array(
                'with' => array('CustomerShipToModel')
            )
        )
    )        
))->findByPk(array(
    'PickTicketNumber'=>$pickTicketNumber,
    'PickTicketLineNumber'=>$pickTicketLineNumber
));

如果这也不起作用，请记录数据库请求并检查查询，如Pentium10在注释中所建议的那样。您可以让phpMyAdmin执行查询，或者使用MySQL“EXPLAIN”关键字获取更多信息。为了获取相关日志，必须将以下行添加到config/main.php文件中：

'components'=>array(
    'db'=>array(
        'enableProfiling' => true,
        'enableParamLogging' => true
    )
)

---

在with（）链之前添加together（）链，如果不起作用，则需要打开sql日志并查看生成的查询together（）不起作用，尽管我不确定它应该做什么。现在，我已经开始使用findByPkU assign

$this->pickTicketLine

分别拉取customerShipTo模型，但是使用

$this->PickTicketLineModel

->PickTicket->SO->CustomerShipToModel，可能：

$this->pickTicketLine

->PickTicket->SO->customershipticketmodel在with（）链之前添加（）链，如果不起作用，您需要打开sql日志并查看生成了什么查询Together（）不起作用，尽管我不确定它应该做什么。现在，我刚开始使用findByPkU assign

$this->pickTicketLine

分别拉取customerShipTo模型，但是使用

$this->pickTicketLine模型

->PickTicket->SO->customerShiptodel，可能：

$this->pickTicketLine

->PickTicket->SO->customerShiptodel您应该能够使用（数组）来做

（'PickTicket.SO.CustomerShipToModel'）

您应该能够使用（数组（'PickTicket.SO.CustomerShipToModel'））执行

。