Php Laravel Swagger获取[Syntax Error]期望值,获取'@';

Php Laravel Swagger获取[Syntax Error]期望值,获取'@';,php,laravel,swagger-php,Php,Laravel,Swagger Php,我已经为控制器中的函数编写了Swagger注释,生成Swagger ui代码时出错。下面是我的注释代码 /*** End of Annotation For deleteNote ***/ /** * @OA\Delete( * path="/api/delete-user-note/{note_id}", * operationId="/api/delete-user-note/{note_id}"

我已经为控制器中的函数编写了Swagger注释,生成Swagger ui代码时出错。下面是我的注释代码

/*** End of Annotation For deleteNote ***/
     /**
     * @OA\Delete(
     *     path="/api/delete-user-note/{note_id}",
     *     operationId="/api/delete-user-note/{note_id}",
     *     tags={"Patient Routes"},
     *      summary= "Delete Note",
     *      description = "Delete Note",
     *      @OA\Parameters(
     *         description="ID note to delete",
     *         in="path",
     *         name="note_id",
     *         required=true,
     *         @OA\Schema(
     *           type="integer",
     *           format="int64"
     *         )
     *     ),
当我运行php artisan l5时,我会大摇大摆地:生成 我犯了一个错误
[语法错误]预期值,获得“@”

您的批注中有错误。请使用以下命令更改您的代码。 您需要将
参数
替换为
参数

/*** End of Annotation For deleteNote ***/
     /**
     * @OA\Delete(
     *     path="/api/delete-user-note/{note_id}",
     *     operationId="/api/delete-user-note/{note_id}",
     *     tags={"Patient Routes"},
     *      summary= "Delete Note",
     *      description = "Delete Note",
     *      @OA\Parameter( //You need to replace Parameters with Parameter
     *         description="ID note to delete",
     *         in="path",
     *         name="note_id",
     *         required=true,
     *         @OA\Schema(
     *           type="integer",
     *           format="int64"
     *         )
     *     ),