Php 错误域=NSCOCAERRORDOMAIN代码=3840“；JSON文本未以数组或对象开头，并且未设置允许片段的选项；斯威夫特3

我正在做一个项目，下面是我的Swift代码。但是当我运行时，我得到了这个错误

Error Domain=NSCocoaErrorDomain code=3840“JSON文本未以数组或对象开头，允许未设置片段的选项。”UserInfo={NSDebugDescription=JSON文本未以数组或对象开头，允许未设置片段的选项。}

我还检查了来自数据库的响应，它说它有一个有效的内容长度。但是由于这个错误，我无法得到我想要的

从我的代码中的响应打印

Optional(<NSHTTPURLResponse: 0x608000233bc0> { URL: http://192.168.1.99/insertData.php } { status code: 200, headers {
    Connection = "Keep-Alive";
    "Content-Length" = 10;
    "Content-Type" = "text/html; charset=UTF-8";
    Date = "Wed, 13 Sep 2017 21:37:38 GMT";
    "Keep-Alive" = "timeout=5, max=100";
    Server = "Apache/2.4.10 (Raspbian)";
} })`

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所以为了完成我的项目，我需要解决这个问题。请帮忙。谢谢。

山姆的回答是这样的

echo（“{”响应“：[{”状态“：“失败”}]}”）；或

echo（“{”Response:[{”status:“success”}，{”userid:“.$userid.}]}”）

试试这个，请告诉我们……：）

let urlOfSMARTCF = URL(string: "http://192.168.1.99/insertData.php")
let request = NSMutableURLRequest(url: urlOfSMARTCF! as URL)   request.httpMethod="POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")

for contact in contactsCaptuure
{
    let userMobileNumber = DBManager.shared.retriveRegisteredNumberOfMobile()    
    let postParameters = "\"usermobilenum\":\(String(describing: userMobileNumber!)),\"contactnum\":\(contact.phoneNumber!)";
    request.httpBody = postParameters.data(using: String.Encoding.utf8)
    let task = URLSession.shared.dataTask(with: request as URLRequest)
    {
        data, response, error in

        if error != nil
        {
            print("error is \(String(describing: error))")
            return;
        }
        do
        {
            print(response)
            let myJSON = try  JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
            if let parseJSON = myJSON
            {
                var msg : String!
                msg = parseJSON["message"] as! String?
                print(msg)

            }
        }
        catch
        {
            print(error.localizedDescription)
            print(error)
        }

    }
    print("Done")
    task.resume()
}