Php Symfony嵌入形式和约束
想象一下这样一个简单的实体Php Symfony嵌入形式和约束,php,symfony-forms,symfony,value-objects,Php,Symfony Forms,Symfony,Value Objects,想象一下这样一个简单的实体 class User { /** * @ORM\Embedded(class="Role") */ protected $role; } class UserType extends AbstractType { /** * @param FormBuilderInterface $builder * @param array $options */ public function buildForm(FormBuild
class User {
/**
* @ORM\Embedded(class="Role")
*/
protected $role;
}
class UserType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('role', RoleType::class);
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(
array(
'data_class' => 'XXXBundle\Entity\User',
'csrf_protection' => false,
)
);
}
}
还有像这样的表格类型
class User {
/**
* @ORM\Embedded(class="Role")
*/
protected $role;
}
class UserType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('role', RoleType::class);
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(
array(
'data_class' => 'XXXBundle\Entity\User',
'csrf_protection' => false,
)
);
}
}
角色实体和角色类型表单
/**
* @ORM\Embeddable()
*/
class Role
{
/**
* @ORM\Column(type="string")
* @Assert\Choice(choices={"foo", "bar"})
*/
private $name;
/**
* Role constructor.
* @param string $name
*/
public function __construct($name)
{
$this->name = $name;
}
/**
* @return string
*/
public function getName(): string
{
return $this->name;
}
}
class RoleType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('name');
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(
array(
'data_class' => 'XXXBundle\Entity\Role',
'empty_data' => function (FormInterface $form) {
return new Role($form->get('name')->getData());
},
)
);
}
}
使用典型的表单->isValid,选择约束断言无法正常工作。。。没有实际验证角色名称值。我找到了Symfony3的解决方案
/**
* @ORM\Embedded(class="Role")
* @Assert\Valid()
*/
protected $role;