Php 如何在多个查询中进行多个字符串替换？

我有一个名为

$querys

的数组，如下所示：

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND StudentID = '%SID%'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '%YEAR%' AND Session%SESSION% = 1; 
)

$variables = array('YEAR' => 2016, 'SESSION' => 1, 'SID' => $_SESSION['sid']);

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '2016' AND Session = '1' AND StudentID = '1234'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '2016' AND Session1 = 1; 
)

我还有第二个数组，名为

$variables

，如下所示：

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND StudentID = '%SID%'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '%YEAR%' AND Session%SESSION% = 1; 
)

$variables = array('YEAR' => 2016, 'SESSION' => 1, 'SID' => $_SESSION['sid']);

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '2016' AND Session = '1' AND StudentID = '1234'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '2016' AND Session1 = 1; 
)

我想用

$variables

中的正确值替换

$querys

中的变量

我已经尝试了许多解决方案，目前为止我想到的最好的解决方案是：

foreach ($queries as $query)
    foreach($variables as $key=>$value)
        $newqueries[] = str_replace("%".$key."%", $value, $query);

但是，这在每个查询中一次只替换一个变量

i、 e.当我这样做时：

foreach ($newqueries as $query)
    print ($query);

每个查询的结果是：

SELECT * FROM StudentRecord 
WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND SID = '%SID%'; 

SELECT * FROM StudentRecord 
WHERE Year = '%YEAR%' AND Session = '1' AND SID = '%SID%';

SELECT * FROM StudentRecord 
WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND SID = '1234';

我想要的是最后一个数组

$newquerys

，如下所示：

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '%YEAR%' AND Session = '%SESSION%' AND StudentID = '%SID%'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '%YEAR%' AND Session%SESSION% = 1; 
)

$variables = array('YEAR' => 2016, 'SESSION' => 1, 'SID' => $_SESSION['sid']);

Array ( 
    [0] => SELECT * FROM StudentRecord WHERE Year = '2016' AND Session = '1' AND StudentID = '1234'; 
    [1] => SELECT * FROM Student_ApplicationRecord WHERE ApplicationYear = '2016' AND Session1 = 1; 
)

有人能帮我吗？如果以前有人问过这个问题，我很抱歉，但是我找不到任何类似的问题。

因为接受了

$search

和

$replace

参数的数组，所以您可以使用它

$search = ['%YEAR%', '%SESSION%', '%SID%'];
$replace = ['2016', '1', $_SESSION['id']];
$newQueries = [];
foreach ($queries as $query) {
    $newQueries[] = str_replace($search, $replace, $query);
}

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为什么不使用带参数绑定的prepared语句呢？