Php 对多个行/列使用一个更新查询

我将如何将代码放入一个UPDATE语句中，记住我正在执行许多条件语句：

    $updateTbl1 =   "UPDATE $tableNameOrig o, $tableNameTemp t SET o.customerAge = t.customerAge WHERE o.id = t.id AND (o.customerAge != t.customerAge );";
    $updateTbl2 =   "UPDATE $tableNameOrig o, $tableNameTemp t SET o.customerCode = t.customerCode WHERE o.id = t.id AND (o.customerCode != t.customerCode);";
    $updateTbl3 =   "UPDATE $tableNameOrig o, $tableNameTemp t SET o.customerName = t.customerName WHERE o.id = t.id AND (o.customerName != t.customerName);";
    $updateTbl4 =   "UPDATE $tableNameOrig o, $tableNameTemp t SET o.customerEmail = t.customerEmail WHERE o.id = t.id AND (o.customerEmail != t.customerEmail);";
    $updateTbl5 =   "UPDATE $tableNameOrig o, $tableNameTemp t SET o.customerAddress = t.customerAddress WHERE o.id = t.id AND (o.customerAddress != t.customerAddress);";
    $updateTbl6 =   "UPDATE $tableNameOrig o, $tableNameTemp t SET o.customerAdded = t.customerAdded WHERE o.id = t.id AND (o.customerAdded != t.customerAdded);";

    (mysqli_query($con,$updateTbl1));
    (mysqli_query($con,$updateTbl2));
    (mysqli_query($con,$updateTbl3));
    (mysqli_query($con,$updateTbl4));
    (mysqli_query($con,$updateTbl5));
    (mysqli_query($con,$updateTbl6));

谢谢

UPDATE $tableNameOrig o
  JOIN $tableNameTemp t
    ON o.id = t.id
   SET o.customerAge = t.customerAge,
       o.customerCode = t.customerCode,
       o.customerName = t.customerName,
       o.customerEmail = t.customerEmail,
       o.customerAddress = t.customerAddress,
       o.customerAdded = t.customerAdded

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您的其他条件是没有意义的。

实际上并没有使用一个

更新

，而是使用一个PHP方法调用，

mysqli\u multi\u查询（$con，$updateTbl1.$updateTbl2）等等。但我只想在值不同时更新它？这就是为什么我要做一个条件测试，因为值不相等。@LazyTotoro是的，但如果值相同，那就没什么大不了的了。。我敢肯定这是最快的方法。MySQL让你知道有多少行是匹配的，有多少行是更改的。我现在意识到了这一点，表中还有一列不会得到批量更新，所以我可以在查询中省去它。谢谢你的帮助和解释！