如何根据PHP中匹配的值推送值

解释

步骤1=>

$first

数组我存储的是类的类型，比如类 1类为A型，2类为A型，3类为 B

步骤2=>

$second

我正在存储类和值的数组键 爱好

步骤3=>

$second

数组我想从

$first

数组中推送

类型

基于类什么是类型

我已经写了PHP代码，我也得到了我预期的结果，但我是两个foreach然后如果条件，我认为这不是正确的方式来写。有没有办法优化我的代码

我的代码

$first = [
    ["class" => "1", "type" => "A"],
    ["class" => "2", "type" => "A"],
    ["class" => "3", "type" => "B"]
];

$second = [
    "1" => ["hobbies" => ["A" , "B"] ],
    "2" => ["hobbies" => ["A" ] ],
    "3" => ["hobbies" => [ "C" ] ]
];

---

由于

$second

中的键与

$first

中的

类

相同，因此可以执行以下操作：

foreach ($first as $item) {
    // check if there's a key `$item['class']` in `$second`:
    if (isset($second[$item['class']])) {
        $second[$item['class']]['type'] = $item['type'];
    }
}

此代码将在

$first

数组上仅使用一个

foreach

Array
(
    [1] => Array
        (
            [hobbies] => Array
                (
                    [0] => A
                    [1] => B
                )

            [Type] => A
        )

    [2] => Array
        (
            [hobbies] => Array
                (
                    [0] => A
                )

            [Type] => A
        )

    [3] => Array
        (
            [hobbies] => Array
                (
                    [0] => C
                )

            [Type] => B
        )

)

foreach ($first as $item) {
    // check if there's a key `$item['class']` in `$second`:
    if (isset($second[$item['class']])) {
        $second[$item['class']]['type'] = $item['type'];
    }
}