解析JSON响应PHP

解析JSON响应PHP,php,json,Php,Json,我有以下JSON数据,我正试图解析这些类别: { "skimlinksProductAPI": { "status": 200, "message": "OK", "version": 3, "categories": { "1": "Animals", "2": "Animals > Live Animals", "3": "Animals > Pet Supplies", "4": "

我有以下JSON数据,我正试图解析这些类别:

{
"skimlinksProductAPI": {
    "status": 200,
    "message": "OK",
    "version": 3,
    "categories": {
        "1": "Animals",
        "2": "Animals > Live Animals",
        "3": "Animals > Pet Supplies",
        "4": "Animals > Pet Supplies > Bird Supplies",
        "5": "Animals > Pet Supplies > Bird Supplies > Bird Cages & Stands",
        "6": "Animals > Pet Supplies > Bird Supplies > Bird Food",
        "7": "Animals > Pet Supplies > Bird Supplies > Bird Ladders & Perches",
        "8": "Animals > Pet Supplies > Bird Supplies > Bird Toys",
        ...
    }
  }
}
我正在尝试以下操作,但不起作用:

$catList = json_decode(file_get_contents('http://api-product.skimlinks.com/categories?key=MY_KEY&format=json'),true);

$catList=$catList['skimlinksProductAPI']['categories'];

foreach ($catList as $element){

    echo $element[0].' - '.$element[1];

}

categories
的元素不是子数组,它们只是键值对。每辆车的
foreach
应该是:

foreach ($catList as $id => $element){
     echo $id . ' - ' . $element;
}

您是否费心检查
json\u last\u error()
并执行
var\u dump($catList)
以查看您得到了什么?不幸的是,这只会给我一个空白页。缺少
echo