Php JSON从android接收数据

Php JSON从android接收数据,php,android,json,http,post,Php,Android,Json,Http,Post,我是php新手。我把数据从android发布到php服务器-- 以及接收php中的数据作为 <?php mysql_connect("localhost","root",""); mysql_select_db("my db"); $var = json_decode($_POST['HTTP_JSON']); $service = $var->{'name'}; mysql_query("INSERT INTO name_table(`_id`, `retrived_na

我是php新手。我把数据从android发布到php服务器--

以及接收php中的数据作为

<?php
 mysql_connect("localhost","root","");
 mysql_select_db("my db");
 $var = json_decode($_POST['HTTP_JSON']);
 $service = $var->{'name'};
 mysql_query("INSERT INTO name_table(`_id`, `retrived_name`, `cat`, `is_valid_name`) VALUES (1547, '$service','$var',true);");
 echo  $var;
?>

您应该在查询中提供值:

<?php
    mysql_connect("localhost","root","");
    mysql_select_db("my db");
    $var = json_decode($_POST['HTTP_JSON']);
    $service = $var->{'name'};
    $name = $_POST['name'];
    mysql_query("INSERT INTO name_table(`_id`, `retrived_name`, `cat`, `is_valid_name`) VALUES (1547, '$service','$name',true);");
    echo  $var;
?>

<?php
    mysql_connect("localhost","root","");
    mysql_select_db("my db");
    $var = json_decode($_POST['HTTP_JSON']);
    $service = $var->{'name'};
    $name = $_POST['name'];
    mysql_query("INSERT INTO name_table(`_id`, `retrived_name`, `cat`, `is_valid_name`) VALUES (1547, '$service','$name',true);");
    echo  $var;
?>