Php JSON从android接收数据
我是php新手。我把数据从android发布到php服务器-- 以及接收php中的数据作为Php JSON从android接收数据,php,android,json,http,post,Php,Android,Json,Http,Post,我是php新手。我把数据从android发布到php服务器-- 以及接收php中的数据作为 <?php mysql_connect("localhost","root",""); mysql_select_db("my db"); $var = json_decode($_POST['HTTP_JSON']); $service = $var->{'name'}; mysql_query("INSERT INTO name_table(`_id`, `retrived_na
<?php
mysql_connect("localhost","root","");
mysql_select_db("my db");
$var = json_decode($_POST['HTTP_JSON']);
$service = $var->{'name'};
mysql_query("INSERT INTO name_table(`_id`, `retrived_name`, `cat`, `is_valid_name`) VALUES (1547, '$service','$var',true);");
echo $var;
?>
您应该在查询中提供值:
<?php
mysql_connect("localhost","root","");
mysql_select_db("my db");
$var = json_decode($_POST['HTTP_JSON']);
$service = $var->{'name'};
$name = $_POST['name'];
mysql_query("INSERT INTO name_table(`_id`, `retrived_name`, `cat`, `is_valid_name`) VALUES (1547, '$service','$name',true);");
echo $var;
?>
<?php
mysql_connect("localhost","root","");
mysql_select_db("my db");
$var = json_decode($_POST['HTTP_JSON']);
$service = $var->{'name'};
$name = $_POST['name'];
mysql_query("INSERT INTO name_table(`_id`, `retrived_name`, `cat`, `is_valid_name`) VALUES (1547, '$service','$name',true);");
echo $var;
?>