PHP中的Regex重复捕获组
我试图从一个包含路由的文件中获取信息,因此在这项工作中,我选择了regex,但我对重复的信息有问题,为了更好地回答这个问题,我将列出我拥有的和我想要的: 因此,我有一个文件:PHP中的Regex重复捕获组,php,regex,Php,Regex,我试图从一个包含路由的文件中获取信息,因此在这项工作中,我选择了regex,但我对重复的信息有问题,为了更好地回答这个问题,我将列出我拥有的和我想要的: 因此,我有一个文件: Codes: C - Connected, S - Static, R - RIP, B - BGP, O - OSPF IntraArea (IA - InterArea, E - External, N - NSSA) A - Aggregate, K - Kernel Remnant, H
Codes: C - Connected, S - Static, R - RIP, B - BGP,
O - OSPF IntraArea (IA - InterArea, E - External, N - NSSA)
A - Aggregate, K - Kernel Remnant, H - Hidden, P - Suppressed,
U - Unreachable, i - Inactive
O E 0.0.0.0/0 via 10.140, bond1.30, cost 1:10, age 5
via 10.141, bond1.31
via 10.142, bond1.32
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O IA 10.138/29 via 10.140, bond1.30, cost 46, age 1029440
C 10.141/29 is directly connected, bond2.35
C 10.141/29 is directly connected, bond2.35
我做了这个正则表达式:
(S|R|B|O|A|K|H|P|U|i) +(IA|E|N|) +([0-9.]+)\/([0-9]+) +via +([0-9.]+), +([a-zA-Z0-9.]+|), +cost +([0-9]+:|)([0-9]+), +age +[0-9]+ +\n(( +via +([0-9.]+), +([a-zA-Z0-9.]+|) +\n)+|)
我的问题是结尾部分(+通过+([0-9.]+),+([a-zA-Z0-9.]+|)+\n)+|)的问题,因为这个正则表达式得到了这个结果
array[0]=>' via 10.141, bond1.31
via 10.142, bond1.32';
array[1]=>'10.142';
array[2]=>'bond1.32';
但是我想
array[0]=>'10.141';
array[1]=>'bond1.31';
array[3]=>'10.142';
array[4]=>'bond1.32';
我在关于regex的页面中测试了regex,其中一个页面告诉我:
注意:重复捕获组只捕获最后一次迭代。
在重复组周围放置一个捕获组以捕获所有
迭代或使用非捕获组(如果不需要)
对数据感兴趣
但我真的不知道这是什么意思,以及如何解决它
注意:这是用于获取的文件是关于cisco中的路由的show ip route
更新1
我把正则表达式改为
(S|R|B|O|A|K|H|P|U|i) +(IA|E|N|) +([0-9.]+)\/([0-9]+) +via +([0-9.]+), +([a-zA-Z0-9.]+|), +cost +([0-9]+:|)([0-9]+), +age +[0-9]+ +\n(?: +via +([0-9.]+), +([a-zA-Z0-9.]+|) +\n)*
这样我就不需要钱了
array[0]=>' via 10.141, bond1.31
via 10.142, bond1.32';
但是我没有重复的部分,恐怕您需要使用另一个正则表达式来获得重复的子模式匹配。所以,你可以这样做:
preg_match_all("/(?:S|R|B|O|A|K|H|P|U|i) +(?:IA|E|N|) +[0-9.]+\/[0-9]+ +via +([0-9.]+), +([a-zA-Z0-9.]+|), +cost +(?:[0-9]+:|)[0-9]+, +age +[0-9]+ +\n((?: +via +[0-9.]+, +(?:[a-zA-Z0-9.]+|) +\n)*)/",$s,$matches,PREG_SET_ORDER);
foreach($matches as $id=>$match)
{
unset($matches[$id][0]);
if(isset($match[3])) {
preg_match_all("/ +via +([0-9.]+), +([a-zA-Z0-9.]+|) +\n/",$match[3],$subpatternMatches,PREG_SET_ORDER);
unset($matches[$id][3]);
foreach($subpatternMatches as $spmid=>$spm) {
unset($subpatternMatches[$spmid][0]);
$matches[$id] = array_merge($matches[$id],$subpatternMatches[$spmid]);
}
}
}
$txt = "Codes: C - Connected, S - Static, R - RIP, B - BGP,
O - OSPF IntraArea (IA - InterArea, E - External, N - NSSA)
A - Aggregate, K - Kernel Remnant, H - Hidden, P - Suppressed,
U - Unreachable, i - Inactive
O E 0.0.0.0/0 via 10.140, bond1.30, cost 1:10, age 5
via 10.141, bond1.31
via 10.142, bond1.32
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O IA 10.138/29 via 10.140, bond1.30, cost 46, age 1029440
C 10.141/29 is directly connected, bond2.35
C 10.141/29 is directly connected, bond2.35
";
$regexp = '#(.) +([A-Z]{1,2}) +([\d.]+/\d+) +via ([\d.]+), ([a-zA-Z0-9.]+), cost [\d:]+, age \d+ +(?:\n +via ([\d.]+), ([a-zA-Z0-9.]+))*#m';
$matches = [];
preg_match_all($regexp, $txt, $matches, PREG_SET_ORDER);
var_dump($matches);
获取示例文件的以下数据:
array(4) {
[0]=>
array(6) {
[0]=>
string(6) "10.140"
[1]=>
string(8) "bond1.30"
[2]=>
string(6) "10.141"
[3]=>
string(8) "bond1.31"
[4]=>
string(6) "10.142"
[5]=>
string(8) "bond1.32"
}
[1]=>
array(2) {
[1]=>
string(6) "10.140"
[2]=>
string(8) "bond1.30"
}
[2]=>
array(2) {
[1]=>
string(6) "10.140"
[2]=>
string(8) "bond1.30"
}
[3]=>
array(2) {
[1]=>
string(6) "10.140"
[2]=>
string(8) "bond1.30"
}
}
好的,我更改了您的regexp,如下所示:
preg_match_all("/(?:S|R|B|O|A|K|H|P|U|i) +(?:IA|E|N|) +[0-9.]+\/[0-9]+ +via +([0-9.]+), +([a-zA-Z0-9.]+|), +cost +(?:[0-9]+:|)[0-9]+, +age +[0-9]+ +\n((?: +via +[0-9.]+, +(?:[a-zA-Z0-9.]+|) +\n)*)/",$s,$matches,PREG_SET_ORDER);
foreach($matches as $id=>$match)
{
unset($matches[$id][0]);
if(isset($match[3])) {
preg_match_all("/ +via +([0-9.]+), +([a-zA-Z0-9.]+|) +\n/",$match[3],$subpatternMatches,PREG_SET_ORDER);
unset($matches[$id][3]);
foreach($subpatternMatches as $spmid=>$spm) {
unset($subpatternMatches[$spmid][0]);
$matches[$id] = array_merge($matches[$id],$subpatternMatches[$spmid]);
}
}
}
$txt = "Codes: C - Connected, S - Static, R - RIP, B - BGP,
O - OSPF IntraArea (IA - InterArea, E - External, N - NSSA)
A - Aggregate, K - Kernel Remnant, H - Hidden, P - Suppressed,
U - Unreachable, i - Inactive
O E 0.0.0.0/0 via 10.140, bond1.30, cost 1:10, age 5
via 10.141, bond1.31
via 10.142, bond1.32
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O IA 10.138/29 via 10.140, bond1.30, cost 46, age 1029440
C 10.141/29 is directly connected, bond2.35
C 10.141/29 is directly connected, bond2.35
";
$regexp = '#(.) +([A-Z]{1,2}) +([\d.]+/\d+) +via ([\d.]+), ([a-zA-Z0-9.]+), cost [\d:]+, age \d+ +(?:\n +via ([\d.]+), ([a-zA-Z0-9.]+))*#m';
$matches = [];
preg_match_all($regexp, $txt, $matches, PREG_SET_ORDER);
var_dump($matches);
这是输出:
array(4) {
[0] =>
array(8) {
[0] =>
string(125) "O E 0.0.0.0/0 via 10.140, bond1.30, cost 1:10, age 5
via 10.141, bond1.31"
[1] =>
string(1) "O"
[2] =>
string(1) "E"
[3] =>
string(9) "0.0.0.0/0"
[4] =>
string(6) "10.140"
[5] =>
string(8) "bond1.30"
[6] =>
string(6) "10.141"
[7] =>
string(8) "bond1.31"
}
[1] =>
array(6) {
[0] =>
string(69) "O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511 "
[1] =>
string(1) "O"
[2] =>
string(1) "E"
[3] =>
string(9) "10.112/23"
[4] =>
string(6) "10.140"
[5] =>
string(8) "bond1.30"
}
[2] =>
array(6) {
[0] =>
string(69) "O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511 "
[1] =>
string(1) "O"
[2] =>
string(1) "E"
[3] =>
string(9) "10.112/23"
[4] =>
string(6) "10.140"
[5] =>
string(8) "bond1.30"
}
[3] =>
array(6) {
[0] =>
string(70) "O IA 10.138/29 via 10.140, bond1.30, cost 46, age 1029440 "
[1] =>
string(1) "O"
[2] =>
string(2) "IA"
[3] =>
string(9) "10.138/29"
[4] =>
string(6) "10.140"
[5] =>
string(8) "bond1.30"
}
}
由于缺少第三个通孔,因此无法工作
新版本,逐行:
$txt = "Codes: C - Connected, S - Static, R - RIP, B - BGP,
O - OSPF IntraArea (IA - InterArea, E - External, N - NSSA)
A - Aggregate, K - Kernel Remnant, H - Hidden, P - Suppressed,
U - Unreachable, i - Inactive
O E 0.0.0.0/0 via 10.140, bond1.30, cost 1:10, age 5
via 10.141, bond1.31
via 10.142, bond1.32
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O E 10.112/23 via 10.140, bond1.30, cost 46:1, age 2511
O IA 10.138/29 via 10.140, bond1.30, cost 46, age 1029440
C 10.141/29 is directly connected, bond2.35
C 10.141/29 is directly connected, bond2.35
";
$grouped = [];
$i = 0;
foreach (explode("\n", $txt) as $line) {
$matches = [];
if (preg_match('#^(.) +([A-Z]{1,2}) +([\d.]+/\d+) +via ([\d.]+), ([a-zA-Z0-9.]+)#', $line, $matches)) {
array_shift($matches);
$grouped[++$i] = $matches;
} else if(preg_match('#^ +via ([\d.]+), ([a-zA-Z0-9.]+)#', $line, $matches)){
array_push($grouped[$i], $matches[1], $matches[2]);
}
}
var_dump($grouped);
现在它正在工作:
array(4) {
[1] =>
array(9) {
[0] =>
string(1) "O"
[1] =>
string(1) "E"
[2] =>
string(9) "0.0.0.0/0"
[3] =>
string(6) "10.140"
[4] =>
string(8) "bond1.30"
[5] =>
string(6) "10.141"
[6] =>
string(8) "bond1.31"
[7] =>
string(6) "10.142"
[8] =>
string(8) "bond1.32"
}
[2] =>
array(5) {
[0] =>
string(1) "O"
[1] =>
string(1) "E"
[2] =>
string(9) "10.112/23"
[3] =>
string(6) "10.140"
[4] =>
string(8) "bond1.30"
}
[3] =>
array(5) {
[0] =>
string(1) "O"
[1] =>
string(1) "E"
[2] =>
string(9) "10.112/23"
[3] =>
string(6) "10.140"
[4] =>
string(8) "bond1.30"
}
[4] =>
array(5) {
[0] =>
string(1) "O"
[1] =>
string(2) "IA"
[2] =>
string(9) "10.138/29"
[3] =>
string(6) "10.140"
[4] =>
string(8) "bond1.30"
}
}
是否要获取第一个O
E
零件的值?通过10.141,每个O
E
可能会出现多少未定义的:可以是无,一个或多个您有相同的问题您只有`[6]=>string(6)“10.141”[7]=>string(8)“bond1.31”`缺少[9]=>string(8)“10.142”[10]=>string(8)“bond1.32”
,但是谢谢你的帮助anwers@nicearma我已经改变了脚本检查出来。似乎是合乎逻辑的,我会尝试它,谢谢,如果所有的工作都很好,我会把答案