php mysql绑定参数仅插入单行

有人能解释为什么下面的代码只在mysql数据库中插入一行吗。 我用echo函数检查数组，它返回两行

$counter=1; // just assume
$orderid=date("mY").'-'.str_pad($counter, 4, '0', STR_PAD_LEFT);
 $stmt = $stmt_connect->prepare("INSERT INTO tblorder_detail(orderid,idno,productid,side,quantity,price,design,days,uploadtime,deliverytime,filecheck,isdelete) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
$i=0;
foreach ($saved_cart_items as $key => $value) { 
$i++;
$isdelete=0;   

$stmt->bind_param("siiiidiissii", $orderid, $i, $value['productid'], $value['side'], $value['quantity'], $value['price'], $value['design'], $value['days'], $value['uploadtime'], $value['deliveryid'], $value['filecheck'], $isdelete  );
$stmt->execute();
}

1：您需要申报$i=1；在外边。否则，第一次$i是未定义的。所以这是投掷错误。在下一个循环中，它将变为1，所以它只插入第二行

第二：您可以像下面那样绑定变量

$stmt = $stmt_connect->prepare("INSERT INTO tblorder_detail(orderid,idno,productid,side,quantity,price,design,days,uploadtime,deliverytime,filecheck,isdelete) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
$stmt->bind_param("siiiidiissii", $orderid, $i, $productid, $side, $quantity, $price, $design, $days, $uploadtime, $deliveryid, $filecheck, $isdelete  );
$i=1;
foreach ($saved_cart_items as $key => $value) { 
$i++;
$isdelete=0;   
$productid = $value['productid'];
$side=$value['side'];
$value['quantity'];
$price= $value['price'];
$design= $value['design'];
$days= $value['days'];
$uploadtime=$value['uploadtime'];
$deliveryid=$value['deliveryid'];
$filecheck=$value['filecheck'];


$stmt->execute();
}

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每次循环后，将表的主id设为null，并声明$i=1；在foreach抱歉代码不完整，我已经声明$i=0；在forreach之前。它只插入一行，即使我通过echo检查数组，它返回的2行是表的主键orderid是主键，$orderid=datemY.'-'。str_pad$counter，4，'0'，str_pad_左；