Php zend framework 2，带连接的分页器

我正在使用zend framework 2编写，但在使用join分页时遇到了一个问题。 我有一个函数：

            if ($paginated) {       
                $select = new \Zend\Db\Sql\Select ();
                $select->from ( 'cliente' );
                $select->columns ( array ('*'), false );
                $select->join ( 'privato', "cliente.idCliente = privato.idCliente", array ('*'), 'left' );
                $select->join ( 'azienda', "cliente.idCliente = azienda.idCliente", array ('*'), 'left' );

                $resultSetPrototype = new ResultSet ();
                $resultSetPrototype->setArrayObjectPrototype ( new Cliente () );
                $paginatorAdapter = new DbSelect ( 
                        $select, 
                        $this->tableGateway->getAdapter ()); 
                        $resultSetPrototype );
                //$paginatorAdapter = $this->tableGateway->selectWith ( $select );
                $paginator = new Paginator ( $paginatorAdapter );
                return $paginator;
            }

            $select = new \Zend\Db\Sql\Select ();
            $select->from ( 'cliente' );
            $select->columns ( array ('*') );
            $select->join ( 'privato', "cliente.idCliente = privato.idCliente", array ('*'), 'left' );
            $select->join ( 'azienda', "cliente.idCliente = azienda.idCliente", array ('*'), 'left' );

            $resultSet = $this->tableGateway->selectWith ( $select );
            return $resultSet;

if语句外的代码工作正常，内部代码号显示以下消息：

            Statement could not be executed (42S21 - 1060 - Duplicate column name 'idCliente')

错误在哪里？ 多谢各位

$select->columns ( array ('idCliente1'=>'idCliente'), false ); 

是因为您必须提供别名，或者在连接上，您可以通过定义所有您想要的列名称来忽略idCliente，例如：

        $select->join ( 'azienda', "cliente.idCliente = azienda.idCliente", array ('column1','column2','etc..'), 'left' );

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你试过我的答案了吗？