Php 使用mysqli返回多行

我正在学习mysqli，我正在尝试查询一个数据库并返回多行。我知道必须使用循环返回多行，但我不知道如何在代码中实现这一点。在此过程中提供一些帮助将不胜感激

$query2 = mysqli_query($con,"SELECT * FROM journeys WHERE id = $id");
$count = mysqli_num_rows($query2);

if ($count == 0) {
    $journeys = 'You have no future journeys.';
} else {
    while ( $row = mysqli_fetch_assoc($query2) ) {      
        $from = $row ['origin'];
        $to = $row ['destination'];
        $date = $row ['date'];
        $hour = $row ['hour'];
        $minute = $row ['minute'];
        $journeyid = $row ['journeyid'];

试试这个代码

    <?php

$con=  mysqli_connect('localhost', 'root', '', 'your data base name');
$query2 = mysqli_query($con,"SELECT * FROM journeys where id=$id");
$count = mysqli_num_rows($query2);

if ($count == 0) {
    $journeys = 'You have no future journeys.';
    echo $journeys;
} else {
    while ( $row = mysqli_fetch_assoc($query2) ) {      
        $from = $row ['origin'];
        $to = $row ['destination'];
        $date = $row ['date'];
        $hour = $row ['our'];
        $minute = $row ['minute'];
        $journeyid =$row ['journeyid'];

        echo $from.'<br>';

    }
}

我加了一行，因为你在这里说，如果$count等于零，那么$journeys='你没有未来的旅程'；但是您没有使用echo，您必须使用echo来显示结果

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如果你仍然有些困惑，请再次询问，并尝试使用谷歌搜索

请在发布问题之前对你的情况做一点调查。一个简单的谷歌搜索给了我很多可能的解决方案。此外，关于如何提问的stackoverflow指南可以在internet上查找一些PHP mysqli示例。通常，当您使用ID列时，您这样做是为了从其他条目中识别唯一的数据行。因此，我假设查询只返回一行的原因是，实际上只有一个条目与查询匹配

    <?php

$con=  mysqli_connect('localhost', 'root', '', 'your data base name');
$query2 = mysqli_query($con,"SELECT * FROM journeys where id=$id");
$count = mysqli_num_rows($query2);

if ($count == 0) {
    $journeys = 'You have no future journeys.';
    echo $journeys;
} else {
    while ( $row = mysqli_fetch_assoc($query2) ) {      
        $from = $row ['origin'];
        $to = $row ['destination'];
        $date = $row ['date'];
        $hour = $row ['our'];
        $minute = $row ['minute'];
        $journeyid =$row ['journeyid'];

        echo $from.'<br>';

    }
}

if ($count == 0) {
    $journeys = 'You have no future journeys.';
    echo $journeys;// i added this line