Php 如何在yii2中的同一视图中获取dropdownlist值

我有一个动态表单中的dropdownlist，如下所示

<?=   $form->field($model, 'emailTemplateId')->dropDownList($emailTemplateIds,
                                   ['prompt'=>'-Choose an Email Template-']   
?>

使用jquery来完成此操作

<?=   $form->field($model, 'emailTemplateId')->dropDownList($emailTemplateIds,
                               ['prompt'=>'-Choose an Email Template-', 'id'=>'select']   
  ?>

  <?= Html::a('Send', ['invoice/send-invoice', 'emailTemplateId' => 0], ['id' => 'send'] ) ?>

 jQuery Part

$("#select").change(function(){
    var text = $("#send").attr("href");
    href = text.replace(/(emailTemplateId=)[^\&]+/, '$1' + $(this).val());
    $("#send").attr("href", href);
})

Use from jquery（选择选项值并将其发送到您的链接）。Jquery帮助链接：实际上，我什么也没有收到
<?=   $form->field($model, 'emailTemplateId')->dropDownList($emailTemplateIds,
                               ['prompt'=>'-Choose an Email Template-', 'id'=>'select']   
  ?>

  <?= Html::a('Send', ['invoice/send-invoice', 'emailTemplateId' => 0], ['id' => 'send'] ) ?>

 jQuery Part

$("#select").change(function(){
    var text = $("#send").attr("href");
    href = text.replace(/(emailTemplateId=)[^\&]+/, '$1' + $(this).val());
    $("#send").attr("href", href);
})