Php 我怎样才能得到这个正则表达式输出？

我的正则表达式在php中有问题。我需要这个来做一些评估，如果我能把这个正则表达式改到右边，那就容易多了。我使用

json\u encode

将最后一个数组转换为json文件

我已经尝试了很多不同的正则表达式，但从来没有得到正确的输出。现在我得到了这样的结果：

[
    [
    "234445 01:00:34.423 ineedhelpineedhelpineedhelppls",
    "234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid",
    ],
    [
    "234445 ",
    "234445 "
    ],
    [
    "01:00:34.423",
    "01:00:34.423"
    ],
    [
    "ineedhelpineedhelpineedhelppls",
    "sdfkkdkkddddddsdfsdfiieuwrepid"
    ]

]

234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234443 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid

我的正则表达式如下所示：

preg\u match\u all（'/（^\d++\s）（01:\w++\s\w++（\s++）/im'，$data，$matches）

如果这样的事情真的很好：

[
    [
    "234445 01:00:34.423 ineedhelpineedhelpineedhelppls",
    "234445",
    "01:00:34.423",
    "ineedhelpineedhelpineedhelppls"
    ],
    [
    "234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid",
    "234445 ",
    "01:00:34.423",
    "sdfkkdkkddddddsdfsdfiieuwrepid"
    ]

]

.log文件如下所示：

[
    [
    "234445 01:00:34.423 ineedhelpineedhelpineedhelppls",
    "234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid",
    ],
    [
    "234445 ",
    "234445 "
    ],
    [
    "01:00:34.423",
    "01:00:34.423"
    ],
    [
    "ineedhelpineedhelpineedhelppls",
    "sdfkkdkkddddddsdfsdfiieuwrepid"
    ]

]

234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
234443 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid

---

您只需使用

PREG\u SET\u ORDER

标志即可：

输出：

Array (
  [0] => Array (
    [0] => 234445 01:00:34.423 ineedhelpineedhelpineedhelppls
    [1] => 234445
    [2] => 01:00:34.423
    [3] => ineedhelpineedhelpineedhelppls
  )
  [1] => Array (
    [0] => 234445 03:04:24.932 sdfkkdkkddddddsdfsdfiieuwrepid
    [1] => 234445
    [2] => 03:04:24.932
    [3] => sdfkkdkkddddddsdfsdfiieuwrepid
  )
)

请注意，您还需要将正则表达式中的

01

更改为

\d+

，以匹配从开始的时间，例如

03

---

请不要尝试使用正则表达式解析JSON。使用合适的JSON解析器。@TimBiegeleisen我不解析JSON，我解析一个.log文件它是一个长日志文件吗？你介意在这里分享一下吗，这样我们也可以测试一下。@R.CanserYanbakan我可以给你一个类似的文件，还有其他的data@R.CanserYanbakan我编辑它