php登录可以脱机工作,但不能联机
大家好,我是PHP新手。我查了w3c,得到了一些好的提示。然而,我的登录代码有一个小挑战。它在第8行的/home/perspect/public\u html/jst/dbcon.PHP:2中显示PHP警告:无法修改标题信息-标题已由(输出开始于/home/perspect/public\u html/jst/index.PHP)发送 下面是我的索引页php登录可以脱机工作,但不能联机,php,Php,大家好,我是PHP新手。我查了w3c,得到了一些好的提示。然而,我的登录代码有一个小挑战。它在第8行的/home/perspect/public\u html/jst/dbcon.PHP:2中显示PHP警告:无法修改标题信息-标题已由(输出开始于/home/perspect/public\u html/jst/index.PHP)发送 下面是我的索引页 <?php session_start(); include_once 'includes/dbcon.php'; if(isset($
<?php
session_start();
include_once 'includes/dbcon.php';
if(isset($_SESSION['user'])!="")
{
header("Location: candidate_list.php");
}
if(isset($_POST['btn-login']))
{
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$stat = 'notvoted';
$res=mysqli_query($con,"SELECT * FROM students WHERE username='$username' AND status='$stat'");
$row=mysqli_fetch_array($res);
if($row['password']==md5($password))
{
$_SESSION['user'] = $row['user_id'];
header("Location: candidate_list.php");
}
else
{
?>
<script>alert('wrong details');</script>
<?php
}
}
?>
<!-- Login Box -->
<div class="col-md-6 col-md-offset-3 col-sm-offset-3">
<form class="login-page" action="" method="post">
<div class="login-header margin-bottom-30">
<h2>Login</h2>
</div>
<div class="input-group margin-bottom-20">
<span class="input-group-addon">
<i class="fa fa-user"></i>
</span>
<input placeholder="VIN" name="username" class="form-control" type="text">
</div>
<div class="input-group margin-bottom-20">
<span class="input-group-addon">
<i class="fa fa-lock"></i>
</span>
<input placeholder="Password" name="password" class="form-control" type="password">
</div>
<div class="row">
<div class="col-md-6">
<button class="btn btn-primary pull-right" type="submit" name="btn-login">Login</button>
</div>
</div>
<p>
</form>
</div>
<!-- End Login Box -->
警报(“错误的详细信息”);
登录
登录
我的candidate_list.php代码是
<?php
session_start();
include_once 'includes/dbcon.php';
if(!isset($_SESSION['user']))
{
header("Location: index.php");
}
$res=mysqli_query($con, "SELECT * FROM students WHERE user_id=".$_SESSION['user']);
$userRow=mysqli_fetch_array($res);
?>
我的dbcon是
<?php
$con=mysqli_connect("xxx","xxx","xxxx","xxx");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
感谢您的帮助。一旦您在头重定向之前回显某些内容,这种类型的php警告就会出现 如果您仍然想重定向,可以使用ob_start或javascript
window.location.href=path是否尝试更改此行:
isset($\u会话['user'])=“
byisset($\u SESSION['user'])
?刚刚尝试过,但仍然不起作用快速检查-在之前是否有空格之前是否真的有空格没有空格,只是检查一下这个想法确实帮了我的忙。。谢谢