Php 尝试获取相同的元素值，然后应用于其他xml

这是我的general.xml文件：-

<?xml version="1.0" encoding="UTF-8"?>
<results>
    <numFound>10</numFound>
    <QTime>4</QTime>
    <result>
        <distance>1071.59873299109</distance>
        <name>Irungattukottai</name>
    </result>
    <result>
            <distance>1892.33578431928</distance>
            <name>Valapuram</name>
       </result>
</results>

此代码是工作性能，但只有一个值，例如：-

general.xml

在第一个

Irungattukottai

和第二个

Valapuram

但我的代码是只获取第一个元素，不尝试获取wall xml文件

这是我的相应输出：-

city Name:- Irungattukottai, Entity_id:- 5079, Product_id:- 1

city Name:- Irungattukottai, Entity_id:- 5079, Product_id:- 1
city Name:- Valapuram , Entity_id:- 7140, Product_id:- 2

但是我想要这种类型的输出：-

city Name:- Irungattukottai, Entity_id:- 5079, Product_id:- 1

city Name:- Irungattukottai, Entity_id:- 5079, Product_id:- 1
city Name:- Valapuram , Entity_id:- 7140, Product_id:- 2

---

您需要迭代$general的数组

试着去做：

echo '<pre>';
print_r($general);
echo '</pre>';

echo'；
印刷（一般）；
回声'；

---

检查是否获得一个包含xml文件中所有元素的数组。

获取general.xml提要的代码正常

您可以按以下方式获取名称：

$xml = simplexml_load_file( 'general.xml' );
$cities = $xml->xpath( '//result/name' );

$cityCount = count( $cities );
if( $cityCount ) {
    $region = simplexml_load_file( 'region.xml' );
    foreach( $cities as $city ) {
        $regions = $region->xpath( '//*[@value="'. ( string ) $city . '"]/@entity_id' );
        if( count ( $regions ) ) {
            $product = simplexml_load_file( 'products.xml' );
            $products = $product->xpath( '//dist_region[@value="' . ( string ) $regions[ 0 ][ 'entity_id' ] . '"]/ancestor::product_id/@value' );
            if( count( $products ) ) {
                foreach( $products as $p ) {
                    echo 'city Name:- ' . ( string ) $city . ', Entity_id:- ' . ( string ) $regions[ 0 ][ 'entity_id' ] . ', Product_id:- ' . $p[ 'value' ] . "\n";
                }
            }
        }
    }
}

$name1=（字符串）$general->result[0]->name；
$name2=（字符串）$general->result[1]->name；
或者可以使用循环逐个获取名称。

试试这个：

city Name:- Irungattukottai, Entity_id:- 5069, Product_id:- 1
city Name:- Irungattukottai, Entity_id:- 5069, Product_id:- 2
city Name:- Valapuram, Entity_id:- 7140, Product_id:- 2

输出

  <?php
    foreach($general->result as $row){
    if(isset($row->name)){
    //create one variable and store in value.
    $name = $row->name;
     //all you code for region.xml and then for product.xml

    }
    echo "name:- $name,Entity:- $entity, product:- $prid"."<br>";
    }

?>

---

使用上述两种答案，可以尝试以下方法：-

尝试执行

打印（$general）@jackphp检查我的答案。我正在尝试这样的foreach循环：-
foreach（$general->result->name as$row）{list（$entity）=$region->xpath（//*[@value='$row']/@entity\id”）；$entity=（string）$entity；list（$prid）=$product->xpath（///dist region[@value='$entity']/祖先：：product\u id/@value”）；$prid=（string）$prid；echo“城市名称：-$row，Entity\u id:-$Entity，Product\u id:-$prid”；}
如果要打印结果$general，则可以看到$general->result->Name不是数组。数组是$general->result。$general->result->Name只会给出您的名字。
city Name:- Irungattukottai, Entity_id:- 5069, Product_id:- 1
city Name:- Irungattukottai, Entity_id:- 5069, Product_id:- 2
city Name:- Valapuram, Entity_id:- 7140, Product_id:- 2

  <?php
    foreach($general->result as $row){
    if(isset($row->name)){
    //create one variable and store in value.
    $name = $row->name;
     //all you code for region.xml and then for product.xml

    }
    echo "name:- $name,Entity:- $entity, product:- $prid"."<br>";
    }

?>