Php 处理我的连接变量以供登录脚本使用

目前我正在使用

$con=mysqli_connect("x","x","x","x");

在登录脚本上处理我的数据库连接。然而，我正在尝试将其转换为OOP风格的方法，例如

$con = new dbclass();
$con->openDB();`

不过我在这方面运气不好

Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\c\login.php on line 103

Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\c\login.php on line 104

Warning: mysqli_query() expects parameter 1 to be mysqli, object given in C:\xampp\htdocs\c\login.php on line 109

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in C:\xampp\htdocs\c\login.php on line 111
Acess denied, wrong username or password?

这就是我用来做这件事的方法

function openDB() {

      $config = include("/assets/configs/db_config.php");
      $conn = mysqli_connect($config["host"] , $config["username"], $config["password"],$config["dbname"]);

// 1. Create a database connection
if (!$conn)
{
    $this->error_msg = "connection error could not connect to the database:! ";  
    return false;
}
$this->conn = $conn;
return true;
}

有人能提些建议吗。我是否需要在我的方法中的某个地方使用mysqli\u connect。或者更好，在我的db_配置文件中：

<?php
     return array("host"=>"x", "dbname"=>"x", "username"=>"x", "password"=>"x");


mysqli_report(MYSQLI_REPORT_ERROR);


?>

include不会导致其中定义的变量成为数组-它们会自动导入到调用函数的作用域中。因为您没有在include文件中定义$config，所以永远不会访问数组

所以，$config=include'your_script.php'并不像您想象的那样

您应该如下更新函数，并将db_config.php中的数组定义更改为定义$host、$username、$password和$dbname

尽管如此，这并不是在OOP应用程序中处理DB连接的最佳方法。如果需要移动配置文件，则必须更新数据库类。最好将变量作为参数传递给openDB函数，然后从控制器中的某个配置脚本中检索它们

例如，以下是更好的做法：

function openDB($username, $password, $dbname, $host = 'localhost') 
{
    $conn = mysqli_connect($host, $username, $password, $dbname);

    if(!$conn)
    {
        $this->error_msg = 'connection error could not connect to the database!';  
        return false;
    }
    $this->conn = $conn;
    return true;
}

---

尝试只使用这个初始化，比如$db=newdb；无需打开数据库，它将已连接

编辑 下面是db_config.php的代码

$db_host = 'localhost';
$db_user = 'root';
$db_password = '';
$db_name = 'bs_admin'; 



class db
{
  public $dbh;
  public $error;
  public $error_msg;


// Create a database connection for use by all functions in this class
function __construct() 
{
  require(dirname(dirname(__FILE__)) . '/config/db_config.php');
if($this->dbh = mysqli_connect($db_host, $db_user, $db_password, $db_name)) 
{ 

  // Set every possible option to utf-8
  mysqli_query($this->dbh, 'SET NAMES "utf8"');
  mysqli_query($this->dbh, 'SET CHARACTER SET "utf8"');
  mysqli_query($this->dbh, 'SET character_set_results = "utf8",' .
    'character_set_client = "utf8", character_set_connection = "utf8",' .
    'character_set_database = "utf8", character_set_server = "utf8"');
} 
else 
{
  // Log an error if the connection fails
  $this->error = true;
  $this->error_msg = 'Unable to connect to DB';

}

// Add a row to any table
public function insert($table,$field_values) 
{
   $query = 'INSERT INTO ' . $table . ' SET ' . $field_values; 
   mysqli_query($this->dbh,$query);       
}

}

---

看起来您刚刚复制了一个通用PHP数据库类。这并不能直接解决OP的问题，因为您没有提到或发布config/db_config.php的代码……我意识到现在已经有点晚了，但我无法在我的方法openDB$name、$pass、$dbname、$host password为空的方法中放置一个空密码对象，因此放置似乎是不可接受的。这有什么办法吗？感谢扩展openDB如下：openDB'root'、'myDB'；应该足够了，不会引起任何问题。。。

$db_host = 'localhost';
$db_user = 'root';
$db_password = '';
$db_name = 'bs_admin'; 



class db
{
  public $dbh;
  public $error;
  public $error_msg;


// Create a database connection for use by all functions in this class
function __construct() 
{
  require(dirname(dirname(__FILE__)) . '/config/db_config.php');
if($this->dbh = mysqli_connect($db_host, $db_user, $db_password, $db_name)) 
{ 

  // Set every possible option to utf-8
  mysqli_query($this->dbh, 'SET NAMES "utf8"');
  mysqli_query($this->dbh, 'SET CHARACTER SET "utf8"');
  mysqli_query($this->dbh, 'SET character_set_results = "utf8",' .
    'character_set_client = "utf8", character_set_connection = "utf8",' .
    'character_set_database = "utf8", character_set_server = "utf8"');
} 
else 
{
  // Log an error if the connection fails
  $this->error = true;
  $this->error_msg = 'Unable to connect to DB';

}

// Add a row to any table
public function insert($table,$field_values) 
{
   $query = 'INSERT INTO ' . $table . ' SET ' . $field_values; 
   mysqli_query($this->dbh,$query);       
}

}