PHP传递mysql查询结果以显示在另一个页面上

抱歉，如果这是一个业余问题，我的PHP技能仍在发展中。我已经用当前代码创建了一个搜索框

<?php    
        // Tyre search setup
        $profileSql = "SELECT DISTINCT `profile` FROM `tyres` WHERE `profile` > 0 ORDER BY `profile`";
        $profileResult = $db->query($profileSql);

        $widthSql = "SELECT DISTINCT `width` FROM `tyres` WHERE `width` > 0 ORDER BY `width`";
        $widthResult = $db->query($widthSql);

        $diamSql = "SELECT DISTINCT `diam` FROM `tyres` WHERE `diam` > 0 ORDER BY `diam`";
        $diamResult = $db->query($diamSql);

        if(isset($_GET['profile']) && isset($_GET['width']) && isset($_GET['diam'])) {
            $profile = $_GET['profile'];
            $width = $_GET['width'];
            $diam = $_GET['diam'];

            $tyreSql = "SELECT * FROM `tyres` WHERE `profile` = " . $profile . " AND `width` = " . $width . " AND  `diam` = " . $diam . " AND rrp > 0 ORDER BY `profile`";
            $tyreResult = $db->query($tyreSql);
        }   
?> 

这是这个逻辑所依赖的形式

<form id="formTyreSearch" name="tyreSearch" method="GET">
    <h2>Tyre Search</h2>
    <p>Use our search below to find the tyre for your car.</p>
        <div class="form-group">Tyre Profile:
            <select name = "diamSearch">
                <?php while($row=mysqli_fetch_assoc($profileResult)) : ?>
                    <option value="<?php echo $row['profile']; ?>"><?php echo $row['profile']; ?></option>
                <?php endwhile; ?>
            </select>
            </div>

       <div class="form-group">Tyre Width:
           <select name = "pcdSearch">
               <?php while($row=mysqli_fetch_assoc($widthResult)) : ?>
                    <option value="<?php echo $row['width']; ?>"><?php echo $row['width']; ?></option>
               <?php endwhile; ?>
            </select>
       </div>

       <div class="form-group">Tyre Diam:
           <select name = "pcdSearch">
               <?php while($row=mysqli_fetch_assoc($diamResult)) : ?>
                    <option value="<?php echo $row['diam']; ?>"><?php echo $row['diam']; ?></option>
               <?php endwhile; ?>
          </select>
      </div>

        <button type="submit" name="filterOptions" value="displayManu" class="btn btn-default btn-sm btn-primary"><i class="fa fa-pencil"></i> Search Now</button>
</form>

轮胎搜查
使用下面的搜索查找您汽车的轮胎

轮胎外形：
轮胎宽度：
轮胎直径：
现在搜索

现在，我假设表单中选择的值是在$tyreResult变量中设置的

---

我想将这个结果传递到一个tires.php页面，并在那里显示搜索结果，这样做的最佳实践是什么？如果用户没有选择所有三个值，我该如何处理，因为网站上还有其他内容，我真的不想重新加载页面并在顶部显示错误…

只需在表单中添加一个

操作

属性，并将结果逻辑移到

tires.php

。如果尚未选择所有值，请将其重定向回上一页。但这不应该发生，除非用户恶意修改你的HTML。默认情况下，将选择

标记的第一个选项

search.php

<?php    
// Tyre search setup
$profileSql = "SELECT DISTINCT `profile` FROM `tyres` WHERE `profile` > 0 ORDER BY `profile`";
$profileResult = $db->query($profileSql);

$widthSql = "SELECT DISTINCT `width` FROM `tyres` WHERE `width` > 0 ORDER BY `width`";
$widthResult = $db->query($widthSql);

$diamSql = "SELECT DISTINCT `diam` FROM `tyres` WHERE `diam` > 0 ORDER BY `diam`";
$diamResult = $db->query($diamSql);
?>

<form id="formTyreSearch" method="get" action="tyres.php">
    <h2>Tyre Search</h2>
    <p>Use our search below to find the tyre for your car.</p>
    <div class="form-group">
        Tyre Profile:
        <select name="profile">
            <?php while ($row = mysqli_fetch_assoc($profileResult)) : ?>
                <option value="<?php echo $row['profile'] ?>"><?php echo $row['profile'] ?></option>
            <?php endwhile ?>
        </select>
    </div>
    <div class="form-group">
        Tyre Width:
        <select name="width">
        <?php while ($row = mysqli_fetch_assoc($widthResult)) : ?>
            <option value="<?php echo $row['width'] ?>"><?php echo $row['width'] ?></option>
        <?php endwhile ?>
        </select>
    </div>
    <div class="form-group">
        Tyre Diam:
        <select name="diam">
        <?php while ($row = mysqli_fetch_assoc($diamResult)) : ?>
            <option value="<?php echo $row['diam'] ?>"><?php echo $row['diam'] ?></option>
        <?php endwhile ?>
        </select>
    </div>
    <button type="submit" name="filterOptions" value="displayManu" class="btn btn-default btn-sm btn-primary">
      <i class="fa fa-pencil"></i> Search Now
    </button>
</form>

<?php
if(isset($_GET['profile'], $_GET['width'], $_GET['diam'])) {
    $profile = $_GET['profile'];
    $width = $_GET['width'];
    $diam = $_GET['diam'];

    $tyreSql = "SELECT * FROM `tyres` WHERE `profile` = " . $profile . " AND `width` = " . $width . " AND  `diam` = " . $diam . " AND rrp > 0 ORDER BY `profile`";
    $tyreResult = $db->query($tyreSql);
} else {
    header('Location: search.php');
    exit;
}
?>

<!-- show the results -->

轮胎搜查
使用下面的搜索查找您汽车的轮胎

轮胎外形：
轮胎宽度：
轮胎直径：
现在搜索

tires.php

<?php    
// Tyre search setup
$profileSql = "SELECT DISTINCT `profile` FROM `tyres` WHERE `profile` > 0 ORDER BY `profile`";
$profileResult = $db->query($profileSql);

$widthSql = "SELECT DISTINCT `width` FROM `tyres` WHERE `width` > 0 ORDER BY `width`";
$widthResult = $db->query($widthSql);

$diamSql = "SELECT DISTINCT `diam` FROM `tyres` WHERE `diam` > 0 ORDER BY `diam`";
$diamResult = $db->query($diamSql);
?>

<form id="formTyreSearch" method="get" action="tyres.php">
    <h2>Tyre Search</h2>
    <p>Use our search below to find the tyre for your car.</p>
    <div class="form-group">
        Tyre Profile:
        <select name="profile">
            <?php while ($row = mysqli_fetch_assoc($profileResult)) : ?>
                <option value="<?php echo $row['profile'] ?>"><?php echo $row['profile'] ?></option>
            <?php endwhile ?>
        </select>
    </div>
    <div class="form-group">
        Tyre Width:
        <select name="width">
        <?php while ($row = mysqli_fetch_assoc($widthResult)) : ?>
            <option value="<?php echo $row['width'] ?>"><?php echo $row['width'] ?></option>
        <?php endwhile ?>
        </select>
    </div>
    <div class="form-group">
        Tyre Diam:
        <select name="diam">
        <?php while ($row = mysqli_fetch_assoc($diamResult)) : ?>
            <option value="<?php echo $row['diam'] ?>"><?php echo $row['diam'] ?></option>
        <?php endwhile ?>
        </select>
    </div>
    <button type="submit" name="filterOptions" value="displayManu" class="btn btn-default btn-sm btn-primary">
      <i class="fa fa-pencil"></i> Search Now
    </button>
</form>

<?php
if(isset($_GET['profile'], $_GET['width'], $_GET['diam'])) {
    $profile = $_GET['profile'];
    $width = $_GET['width'];
    $diam = $_GET['diam'];

    $tyreSql = "SELECT * FROM `tyres` WHERE `profile` = " . $profile . " AND `width` = " . $width . " AND  `diam` = " . $diam . " AND rrp > 0 ORDER BY `profile`";
    $tyreResult = $db->query($tyreSql);
} else {
    header('Location: search.php');
    exit;
}
?>

<!-- show the results -->

我建议将结果转换为JSON并使用POST将数据发送到其他页面。你不需要表格。只需获取JSON并在结果对象中再次转换即可。检查此项以了解如何在PHP中管理JSON数据。然后检查curl，将JSON数据发布到另一个PHP页面。嘿，Mikey，似乎没有传递值，只是在标题中有tires.PHP？tyreSearch=。也不能使用标题（'Location:'），因为我收到了以下错误警告：无法修改标题信息-标题已经由第55行的\tyres.php中的\tyres.php发送（输出开始于includes\quickModalTyres.inc.php:127），55是标题，127行是奇怪的。我希望

tires.php？pcdSearch=

基于您的原始代码。您需要为您的

标记指定唯一的名称，如我修订的HTML代码所示。就警告而言，这是因为您在代码中较早地开始了输出缓冲。查看此链接以了解有关如何修复此警告的更多信息。嘿，Mikey，谢谢我进行了另一次查看并对其进行了更改，我可能会在以后的某个日期将其编辑为用例，这样任何一个参数都可以单独使用，但这是另一天的事情。我会看看那篇文章，模态已经给了我一段时间的问题（ob_get_clean就是在这里被称为ob_clean的）。