使用php解析参数时出错
此代码将输出显示为: 字符串(59)“{”状态“{”消息“:“错误分析” 参数“,”值“:14}” 但是当使用“使用php解析参数时出错,php,mysql,Php,Mysql,此代码将输出显示为: 字符串(59)“{”状态“{”消息“:“错误分析” 参数“,”值“:14}” 但是当使用“file\u get\u contents”而不是“echo”时,它会将正确的url显示为输出:http://ws.geonames.org/countryCodeJSON?lat=20.992&lng=73.314&username=**** 这里出了什么问题 <?php $servername = "localhost"; $username = "****
file\u get\u contents
”而不是“echo
”时,它会将正确的url显示为输出:http://ws.geonames.org/countryCodeJSON?lat=20.992&lng=73.314&username=****
这里出了什么问题
<?php
$servername = "localhost";
$username = "*******";
$password = "*************";
$dbname = "id1116502_kk";
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//remove limit 1 is you want multiple data.
$sql = "SELECT degree_n, minute_n,degree_e, minute_e FROM coordinates ORDER BY id DESC limit 1 ";
$result = $conn->query($sql);
$deg_e = "";
$min_e = "";
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$deg_n = $row["degree_n"];
$min_n = $row["minute_n"];
$deg_e = $row["degree_e"];
$min_e = $row["minute_e"];
$url = file_get_contents('http://ws.geonames.org/countryCodeJSON?lat=$deg_n.$min_n&lng=$deg_e.$min_e&username=****');
var_dump($url);
}
} else {
echo "0 results";
}
$conn->close();
?>
您在文件\u get\u内容中使用单引号
// change this to double quotes
$url = file_get_contents('http://ws.geonames.org/countryCodeJSON?lat=$deg_n.$min_n&lng=$deg_e.$min_e&username=krunal123');
您在tour
文件中使用单引号获取内容
thnx…已解决…嗯,像echo这样的东西是不可能的http://ws.geonames.org/countryCodeJSON?lat=$deg_n.$min_n&lng=$deg_e.$min_e&username=**代码>解析变量。