Php 使用来自不同查询的数据合并2个表？

我目前有两个表，如下所示：

<table width="600" border="1">  
<tr>   
   <th width="91"> <div align="center">Mail_ID  </div></th> 
   <th width="91"> <div align="center">Status  </div></th> 
   <th width="91"> <div align="center">Datum  </div></th> 
</tr>
<?php 
$j = 0;  
while($objResult2 = mysql_fetch_array($objQuery2))  
{  
$j++;  
?> 
<tr>   
   <td><div align="center"><?=$objResult2["Mail_ID"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Status"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Datum"];?> </div></td>  
</tr>
<?php  
}  
?>
</table>
<br/>
<table width="600" border="1">  
<tr> 
   <th width="91"> <div align="center">ID  </div></th>  
   <th width="91"> <div align="center">Titel  </div></th> 
   <th width="91"> <div align="center">Subscribe  </div></th> 
   <th width="91"> <div align="center">Unsubscribe  </div></th> 
</tr>

<?php for ($i = 0; $objResult1 = mysql_fetch_array($objQuery1); $i++) : ?>
<tr>  
    <td><div align="center"><?=$objResult1["ID"];?><input type="hidden" name="mailid[]" value="<?=$objResult1["ID"];?>"> </div></td>
    <td><div align="center"><?=$objResult1["Titel"];?> </div></td>  
    <td><div align="center"><input type="radio" name="sub[<?php echo $i; ?>]" value="10"> </div></td>  
    <td><div align="center"><input type="radio" name="sub[<?php echo $i; ?>]" value="90"> </div></td> 
</tr>
<?php endfor; ?>

</table>  

$strSQL1    = "SELECT ID, Titel FROM Mail"; 
$strSQL2    = "SELECT * FROM Subscriptions,
(SELECT MAX(ID) as ids, Mail_ID FROM Subscriptions
    WHERE Klant_ID = '".$_GET["ID"]."' GROUP BY Mail_ID) table2
WHERE ID=table2.ids";  
$objQuery1  = mysql_query($strSQL1);
$objQuery2     = mysql_query($strSQL2); 

这两个表的代码如下所示：

<table width="600" border="1">  
<tr>   
   <th width="91"> <div align="center">Mail_ID  </div></th> 
   <th width="91"> <div align="center">Status  </div></th> 
   <th width="91"> <div align="center">Datum  </div></th> 
</tr>
<?php 
$j = 0;  
while($objResult2 = mysql_fetch_array($objQuery2))  
{  
$j++;  
?> 
<tr>   
   <td><div align="center"><?=$objResult2["Mail_ID"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Status"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Datum"];?> </div></td>  
</tr>
<?php  
}  
?>
</table>
<br/>
<table width="600" border="1">  
<tr> 
   <th width="91"> <div align="center">ID  </div></th>  
   <th width="91"> <div align="center">Titel  </div></th> 
   <th width="91"> <div align="center">Subscribe  </div></th> 
   <th width="91"> <div align="center">Unsubscribe  </div></th> 
</tr>

<?php for ($i = 0; $objResult1 = mysql_fetch_array($objQuery1); $i++) : ?>
<tr>  
    <td><div align="center"><?=$objResult1["ID"];?><input type="hidden" name="mailid[]" value="<?=$objResult1["ID"];?>"> </div></td>
    <td><div align="center"><?=$objResult1["Titel"];?> </div></td>  
    <td><div align="center"><input type="radio" name="sub[<?php echo $i; ?>]" value="10"> </div></td>  
    <td><div align="center"><input type="radio" name="sub[<?php echo $i; ?>]" value="90"> </div></td> 
</tr>
<?php endfor; ?>

</table>  

$strSQL1    = "SELECT ID, Titel FROM Mail"; 
$strSQL2    = "SELECT * FROM Subscriptions,
(SELECT MAX(ID) as ids, Mail_ID FROM Subscriptions
    WHERE Klant_ID = '".$_GET["ID"]."' GROUP BY Mail_ID) table2
WHERE ID=table2.ids";  
$objQuery1  = mysql_query($strSQL1);
$objQuery2     = mysql_query($strSQL2); 

现在我想合并这两个表，如下所示：

<table width="600" border="1">  
<tr>   
   <th width="91"> <div align="center">Mail_ID  </div></th> 
   <th width="91"> <div align="center">Status  </div></th> 
   <th width="91"> <div align="center">Datum  </div></th> 
</tr>
<?php 
$j = 0;  
while($objResult2 = mysql_fetch_array($objQuery2))  
{  
$j++;  
?> 
<tr>   
   <td><div align="center"><?=$objResult2["Mail_ID"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Status"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Datum"];?> </div></td>  
</tr>
<?php  
}  
?>
</table>
<br/>
<table width="600" border="1">  
<tr> 
   <th width="91"> <div align="center">ID  </div></th>  
   <th width="91"> <div align="center">Titel  </div></th> 
   <th width="91"> <div align="center">Subscribe  </div></th> 
   <th width="91"> <div align="center">Unsubscribe  </div></th> 
</tr>

<?php for ($i = 0; $objResult1 = mysql_fetch_array($objQuery1); $i++) : ?>
<tr>  
    <td><div align="center"><?=$objResult1["ID"];?><input type="hidden" name="mailid[]" value="<?=$objResult1["ID"];?>"> </div></td>
    <td><div align="center"><?=$objResult1["Titel"];?> </div></td>  
    <td><div align="center"><input type="radio" name="sub[<?php echo $i; ?>]" value="10"> </div></td>  
    <td><div align="center"><input type="radio" name="sub[<?php echo $i; ?>]" value="90"> </div></td> 
</tr>
<?php endfor; ?>

</table>  

$strSQL1    = "SELECT ID, Titel FROM Mail"; 
$strSQL2    = "SELECT * FROM Subscriptions,
(SELECT MAX(ID) as ids, Mail_ID FROM Subscriptions
    WHERE Klant_ID = '".$_GET["ID"]."' GROUP BY Mail_ID) table2
WHERE ID=table2.ids";  
$objQuery1  = mysql_query($strSQL1);
$objQuery2     = mysql_query($strSQL2); 

---

我无法让它工作，因为我尝试的每件事都会因为里面的两个循环而混淆。我希望你们能理解我的问题，我添加了尽可能多的信息和图片，让一切都清楚了^^如果你们还有问题，请以评论的形式询问他们。欢迎任何帮助

我不确定这对您来说是否是一个完整的解决方案，但这应该是一个开始：

SELECT Mail.ID Mail_ID, Mail.Titel, Subscriptions.status, Subscriptions.Datum, Subscriptions.Subscribe, Subscriptions.Unsubscribe
FROM Mail left join Subscriptions on Mail.ID = Subscriptions.Mail_ID

---

使用SQL联接形成一个返回所有数据的SQL查询。然后只使用一个循环

SQL可能类似于：

SELECT ID, Titel, Subscriptions.* FROM Mail INNER JOIN Subscriptions ON Subscriptions.ID = Mail.ID ...

---

你应该像其他人说的那样使用连接。通过连接两个或多个表，您不需要使用多个while循环，这样代码会更干净

SELECT 
  Mail.ID Mail_ID,
  Mail.Titel,
  Subscriptions.status,
  Subscriptions.Datum,
  Subscriptions.Subscribe,
  Subscriptions.Unsubscribe 
FROM
  Mail 
LEFT JOIN Subscriptions 
ON (Subscriptions.Mail_ID = Mail.ID)

其中一种联接类型应该适合您：左联接或内联接

HTML应该如下所示：

<table width="600" border="1">  
<tr>   
   <th width="91"> <div align="center">Mail_ID  </div></th> 
   <th width="91"> <div align="center">Status  </div></th> 
   <th width="91"> <div align="center">Datum  </div></th> 
   <th width="91"> <div align="center">Titel  </div></th> 
   <th width="91"> <div align="center">Subscribe  </div></th> 
   <th width="91"> <div align="center">Unsubscribe  </div></th> 
</tr>
<?php 
while ($objResult2 = mysql_fetch_array($objQuery2))  
{
?> 
<tr>   
   <td><div align="center"><?=$objResult2["Mail_ID"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Status"];?> </div></td> 
   <td><div align="center"><?=$objResult2["Datum"];?> </div></td>  
   <td><div align="center"><?=$objResult1["Mail_ID"];?><input type="hidden" name="mailid[]" value="<?=$objResult1["Mail_ID"];?>"> </div></td>
   <td><div align="center"><?=$objResult1["Titel"];?> </div></td>  
   <td><div align="center"><input type="radio" name="sub[<?=$objResult1["Subscriptions_ID"];?>]" value="10"> </div></td>  
   <td><div align="center"><input type="radio" name="sub[<?=$objResult1["Subscriptions_ID"];?>]" value="90"> </div></td> 
</tr>
<?php
}
?>
</table>  

邮件ID
地位
资料
滴度
订阅
退订
调查请参见中的示例