Php 如果文件已经存在,我需要复制并重命名该文件的副本

Php 如果文件已经存在,我需要复制并重命名该文件的副本,php,file-upload,filenames,file-rename,Php,File Upload,Filenames,File Rename,如果文件副本已经存在,则需要复制并重命名该副本 $pastaTemp = $_FILES['imagem_principal']['tmp_name']; $pastaUpload = $_SERVER['DOCUMENT_ROOT']."/casaunica/imagens/acabamentos/"; $arquivo = $pastaUpload . $_FILES['imagem_principal']['name']; //filename.jpg if(!file_exists($

如果文件副本已经存在,则需要复制并重命名该副本

$pastaTemp = $_FILES['imagem_principal']['tmp_name'];
$pastaUpload = $_SERVER['DOCUMENT_ROOT']."/casaunica/imagens/acabamentos/";
$arquivo = $pastaUpload . $_FILES['imagem_principal']['name']; //filename.jpg

if(!file_exists($pastaUpload. $_FILES['imagem_principal']['name'])){
      $arquivo = $pastaUpload . $_FILES['imagem_principal']['name'];
} else {
    $nome_arquivo = explode(".",$_FILES['imagem_principal']['name']);
       do {
          $para = $nome_arquivo[0]."_".$i.".".$nome_arquivo[1];
          $nome_novo = rename($arquivo, $pastaUpload . $para);
          $arquivo = $pastaUpload .$nome_novo;
          $i++; 
       } while(file_exists($pastaUpload.$_FILES['imagem_principal']['name']));
}
输出:filename.jpg_1

它应该是:filename_2.jpg

它无法替换旧文件。。这就是为什么我需要用一个数字来重命名
它不需要在循环中创建,但每次上载文件时,请尝试此代码,让我知道它是否有效

功能

<?php
  function recursive_naming( $file, $i = 1 ) {
    $dirname    = dirname( $file ).DIRECTORY_SEPARATOR;
    $filename   = pathinfo( $file, PATHINFO_FILENAME );
    $extension  = pathinfo( $file, PATHINFO_EXTENSION );

    if ( !file_exists( $file ) ) {
      return $file;
    }
    $filename = preg_replace( '/_\d+$/', '', $filename );
    $file = $dirname.$filename."_".$i.".".$extension;
    $i++;
    return recursive_naming( $file, $i );
  }
?>

示例:

<?php
  $pastaTemp    = $_FILES['imagem_principal']['tmp_name'];
  $pastaUpload  = $_SERVER['DOCUMENT_ROOT']."/casaunica/imagens/acabamentos/";
  $arquivo      = recursive_naming( $pastaUpload.$_FILES['imagem_principal']['name'] );
?>


它将输出
filename\u 2.jpg
如果
filename.jpg
存在,或者
filename\u 3.jpg
如果
filename\u 2.jpg
也存在,等等…

看起来分解没有按您希望的方式工作分解工作,可能重命名函数错误,或者我应该使用另一个函数。您是否尝试过回显$para?这句话似乎是问题最明显的根源,虽然我看不出我做了什么特别错误的事情,它是正确的,我已经改变了做了一段时间,它工作了,但它取代了旧文件你能帮我吗??