Php 删除空JSON参数
我已经设置了一系列变量及其值:Php 删除空JSON参数,php,json,Php,Json,我已经设置了一系列变量及其值: $exp = "1642873358"; $country_code = "LO"; $item_description = "An item"; $language_code = ""; $price_amount = "5.99"; $price_currency = "EUR"; $urls_authorisation_callback = "https://www.example.com/"; $urls_redirect = "https://www.e
$exp = "1642873358";
$country_code = "LO";
$item_description = "An item";
$language_code = "";
$price_amount = "5.99";
$price_currency = "EUR";
$urls_authorisation_callback = "https://www.example.com/";
$urls_redirect = "https://www.example.com/";
$urls_unsubscription_redirect = "";
$subscription_duration = "";
$subscription_unit = "";
$subscription_cycles = "";
$subscription_price_amount = "";
$subscription_price_currency = "";
$msisdn = "55555555";
$msisdn_edit_disabled = "";
这些变量值应该是可编辑的,如果愿意,可以保留为空,如示例所示。我不想删除这个变量
然后我创建了一个数组,该数组后来被编码为JSON:
$token = array(
'exp' => "$exp" ,
'country_code' => "$country_code",
'item_description' => "$item_description",
'language_code' => "$language_code",
'price' => array(
'amount' => "$price_amount",
'currency' => "$price_currency"
),
'urls' => array(
'authorisation_callback' => "$urls_authorisation_callback",
'redirect' => "$urls_redirect",
'unsubscription_redirect' => "$urls_unsubscription_redirect"
),
'subscription' => array(
'duration' => "$subscription_duration",
'unit' => "$subscription_unit" ,
'cycles' => "$subscription_cycles" ,
'price' => array(
'amount' => "$subscription_price_amount",
'currency' => "$subscription_price_currency"
)
),
'msisdn' => "$msisdn",
'msisdn_edit_disabled' => "$msisdn_edit_disabled"
);
当我最终回显JSON文本时:
echo json_encode($token, JSON_PRETTY_PRINT) . "\n";
我得到以下信息:
{
"exp": "1642873358",
"country_code": "LO",
"item_description": "An item",
"language_code": "",
"price": {
"amount": "5.99",
"currency": "EUR"
},
"urls": {
"authorisation_callback": "https:\/\/www.example.com\/",
"redirect": "https:\/\/www.example.com\/",
"unsubscription_redirect": ""
},
"subscription": {
"duration": "",
"unit": "",
"cycles": "",
"price": {
"amount": "",
"currency": ""
}
},
"msisdn": "55555555",
"msisdn_edit_disabled": ""
}
如果要删除未指定值的参数,有哪些选项?以一种不会弄乱所需JSON结构的方式。给定示例中的预期结果为:
{
"exp": "1642873358",
"country_code": "LO",
"item_description": "An item",
"price": {
"amount": "5.99",
"currency": "EUR"
},
"urls": {
"authorisation_callback": "https:\/\/www.example.com\/",
"redirect": "https:\/\/www.example.com\/"
},
"msisdn": "55555555"
}
将其转换为和数组。使用json_解码 然后使用下面的递归函数删除空值。然后再次编码为json
function array_remove_empty($haystack)
{
foreach ($haystack as $key => $value) {
if (is_array($value)) {
$haystack[$key] = array_remove_empty($haystack[$key]);
}
if (empty($haystack[$key])) {
unset($haystack[$key]);
}
}
return $haystack;
}
$token = array_remove_empty($token);
在创建之前,请检查该值是否为空。不应手动更改json。您应该只添加以值开头的参数,或者在json编码之前遍历数组并删除所有空参数。您不需要将数组项创建为字符串,例如,
'amount'=>“$price\u amount”
-您只需编写'amount'=>$price\u amount
。这还允许您在JSON中以实际数字而不是字符串的形式显示数字。在副本中,定义函数array\u filter\u recursive()
的答案应该在后面执行。这应该在编码为JSON之前在数组上运行。另请参阅,这表明这通常比递归的数组\u过滤器
更快。