Php 卷曲没有显示正确的东西

有人告诉我使用CURL绕过cloudflare在网站上获取文本，所以我尝试了一下，但我就是不明白我是如何回音的

$link1 = "http://habmoon.org/moonstream/djlook?habbie={$r->habbo}";
$link2 = "https://www.habbo.com/habbo-imaging/avatarimage?figure={$link1}";                 
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $link1);
    curl_exec($ch);
    curl_close($ch);

---

它显示的唯一内容是$link1，因为我不知道如何从

curl\u setopt（$ch，CURLOPT\u URL，$link1）回显文本在$link2中。
你好，朋友您需要使用CURLOPT_RETURNTRANSFER来获取请求输出：

$link1 = "http://habmoon.org/moonstream/djlook?habbie={$r->habbo}";
$link2 = "https://www.habbo.com/habbo-imaging/avatarimage?figure={$link1}";                 
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $link1);
    curl_exec($ch);
    curl_close($ch);

$ch = curl_init();

$opts = [
    CURLOPT_URL => 'a site',
    CURLTOP_RETURNTRANSFER => TRUE
];

curl_setopt_array($opts);
$response = curl_exec($ch);

var_dump($response);

请记住，如果需要请求https，请使用ca文件或：

$link1 = "http://habmoon.org/moonstream/djlook?habbie={$r->habbo}";
$link2 = "https://www.habbo.com/habbo-imaging/avatarimage?figure={$link1}";                 
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $link1);
    curl_exec($ch);
    curl_close($ch);

CURLOPT_SSL_VERIFYPEER => FALSE
CURLOPT_SSL_VERIFYHOST => FALSE

祝你好运

$link1 = "http://habmoon.org/moonstream/djlook?habbie={$r->habbo}";
$link2 = "https://www.habbo.com/habbo-imaging/avatarimage?figure={$link1}";                 
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $link1);
    curl_exec($ch);
    curl_close($ch);