Php 在CustomExceptionController中访问redirectToRoute

在/src/AppBundle/Controller/CustomExceptionController.php中，我有：

namespace AppBundle\Controller;

use Symfony\Component\Debug\Exception\FlattenException;
use Symfony\Component\HttpKernel\Log\DebugLoggerInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;

class CustomExceptionController extends \Symfony\Bundle\TwigBundle\Controller\ExceptionController
{

    public function showAction(Request $request, FlattenException $exception, DebugLoggerInterface $logger = null)
    {
        return $this->redirectToRoute('custom_error'); //not working
    }
}

---

这不起作用，因为\Symfony\Bundle\TwigBundle\Controller\ExceptionController未扩展类控制器。那么，我如何在这个类中使用$this->redirectToRoute呢？

redirectToRoute

就像您提到的那样是

控制器

类的一部分。 您所需要做的就是自己创建方法

首先，您需要将路由器注入

CustomExceptionController

（因此您需要将自定义控制器定义为DI中的服务）

您的自定义类应如下所示：

class CustomExceptionController extends \Symfony\Bundle\TwigBundle\Controller\ExceptionController
{
    protected $router;

    public function __construct(\Twig_Environment $twig, $debug, Router $router)
    {
        parent::__construct($twig, $debug);
        $this->router = $router;
    }

    public function showAction(Request $request, FlattenException $exception, DebugLoggerInterface $logger = null)
    {

    }
}

之后，您可以像在控制器中一样在CustomExceptionController中实现redirectToRoute（或者直接创建RedirectResponse而不使用helper方法）

---

使用UrlGeneratorInterface-like的简单方法

 getContainer()->get('router')->generate( 'custom_error', ['key' => 'some val'], 0 );

getContainer（）-是自己的函数，请参阅手册

/**
 * Returns a RedirectResponse to the given URL.
 *
 * @param string $url    The URL to redirect to
 * @param int    $status The status code to use for the Response
 *
 * @return RedirectResponse
 */
public function redirect($url, $status = 302)
{
    return new RedirectResponse($url, $status);
}

/**
 * Returns a RedirectResponse to the given route with the given parameters.
 *
 * @param string $route      The name of the route
 * @param array  $parameters An array of parameters
 * @param int    $status     The status code to use for the Response
 *
 * @return RedirectResponse
 */
protected function redirectToRoute($route, array $parameters = array(), $status = 302)
{
    return $this->redirect($this->router->generateUrl($route, $parameters), $status);
}

 getContainer()->get('router')->generate( 'custom_error', ['key' => 'some val'], 0 );

// src/Service/SomeService.php

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;

class SomeService
{
    private $router;

    public function __construct(UrlGeneratorInterface $router)
    {
        $this->router = $router;
    }

    public function someMethod()
    {
        $url = $this->router->generate( 'custom_error', [ 'key' => 'some value' ] );

    }
}