Php 将json数据存储在局部变量中

我从

URL

获取

youtube视频的
gdata
。它返回如下所示的
json代码

{"apiVersion":"2.1","data":{"id":"4TSJhIZmL0A","uploaded":"2008-07-15T18:11:59.000Z","updated":"2013-05-01T21:01:49.000Z","uploader":"burloandbardsey","category":"News","title":"bbc news start up theme","description":"bbc","thumbnail":{"sqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/default.jpg","hqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/hqdefault.jpg"},"player":{"default":"http://www.youtube.com/watch?v=4TSJhIZmL0A&feature=youtube_gdata_player","mobile":"http://m.youtube.com/details?v=4TSJhIZmL0A"},"content":{"5":"http://www.youtube.com/v/4TSJhIZmL0A?version=3&f=videos&app=youtube_gdata","1":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp","6":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"},"duration":15,"aspectRatio":"widescreen","rating":4.6683936,"likeCount":"354","ratingCount":386,"viewCount":341066,"favoriteCount":0,"commentCount":155,"accessControl":{"comment":"allowed","commentVote":"allowed","videoRespond":"allowed","rate":"allowed","embed":"allowed","list":"allowed","autoPlay":"allowed","syndicate":"allowed"}}}

但是我只在我的
远程服务器上连接
互联网
，而不是
本地系统

现在我的问题是,

出于测试目的，在使用
json_decode（）
之前，我想将上述
json code
存储在局部变量中。
但是它给出了
语法错误

比如说,

$myJson = {"apiVersion":"2.1","data":{"id":"4TSJhIZmL0A","uploaded":"2008-07-15T18:11:59.000Z","updated":"2013-05-01T21:01:49.000Z","uploader":"burloandbardsey","category":"News","title":"bbc news start up theme","description":"bbc","thumbnail":{"sqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/default.jpg","hqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/hqdefault.jpg"},"player":{"default":"http://www.youtube.com/watch?v=4TSJhIZmL0A&feature=youtube_gdata_player","mobile":"http://m.youtube.com/details?v=4TSJhIZmL0A"},"content":{"5":"http://www.youtube.com/v/4TSJhIZmL0A?version=3&f=videos&app=youtube_gdata","1":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp","6":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"},"duration":15,"aspectRatio":"widescreen","rating":4.6683936,"likeCount":"354","ratingCount":386,"viewCount":341066,"favoriteCount":0,"commentCount":155,"accessControl":{"comment":"allowed","commentVote":"allowed","videoRespond":"allowed","rate":"allowed","embed":"allowed","list":"allowed","autoPlay":"allowed","syndicate":"allowed"}}};

如何在局部变量中存储我的
json数据

$myJson = '{"apiVersion":"2.1","data":{"id":"4TSJhIZmL0A","uploaded":"2008-07-15T18:11:59.000Z","updated":"2013-05-01T21:01:49.000Z","uploader":"burloandbardsey","category":"News","title":"bbc news start up theme","description":"bbc","thumbnail":{"sqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/default.jpg","hqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/hqdefault.jpg"},"player":{"default":"http://www.youtube.com/watch?v=4TSJhIZmL0A&feature=youtube_gdata_player","mobile":"http://m.youtube.com/details?v=4TSJhIZmL0A"},"content":{"5":"http://www.youtube.com/v/4TSJhIZmL0A?version=3&f=videos&app=youtube_gdata","1":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp","6":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"},"duration":15,"aspectRatio":"widescreen","rating":4.6683936,"likeCount":"354","ratingCount":386,"viewCount":341066,"favoriteCount":0,"commentCount":155,"accessControl":{"comment":"allowed","commentVote":"allowed","videoRespond":"allowed","rate":"allowed","embed":"allowed","list":"allowed","autoPlay":"allowed","syndicate":"allowed"}}}';

如果有效，则需要用“”或“”将字符串包围。在任何情况下，在字符串中转义“and”都是一个好主意。
将其存储在
'
类似字符串的内部，如下所示

$myJson = '{"apiVersion":"2.1","data":{"id":"4TSJhIZmL0A","uploaded":"2008-07-15T18:11:59.000Z","updated":"2013-05-01T21:01:49.000Z","uploader":"burloandbardsey","category":"News","title":"bbc news start up theme","description":"bbc","thumbnail":{"sqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/default.jpg","hqDefault":"http://i.ytimg.com/vi/4TSJhIZmL0A/hqdefault.jpg"},"player":{"default":"http://www.youtube.com/watch?v=4TSJhIZmL0A&feature=youtube_gdata_player","mobile":"http://m.youtube.com/details?v=4TSJhIZmL0A"},"content":{"5":"http://www.youtube.com/v/4TSJhIZmL0A?version=3&f=videos&app=youtube_gdata","1":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp","6":"rtsp://v5.cache7.c.youtube.com/CiILENy73wIaGQlAL2aGhIk04RMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"},"duration":15,"aspectRatio":"widescreen","rating":4.6683936,"likeCount":"354","ratingCount":386,"viewCount":341066,"favoriteCount":0,"commentCount":155,"accessControl":{"comment":"allowed","commentVote":"allowed","videoRespond":"allowed","rate":"allowed","embed":"allowed","list":"allowed","autoPlay":"allowed","syndicate":"allowed"}}}';

将JSON存储为字符串我已经用代码的方式检查了它。但是我的JSON值有任何
'
或
'“
意味着它将结束。这就是为什么我说你应该逃离那些魔咒；-）如果不在局部变量中指定此json值，如何进行转义？有可能吗？这取决于你如何获取数据，但你可以使用str_replace或addslashes。有关如何使用的参考信息，请参见php.netthem@YogeshSuthar：是的。但是本例中没有
引号
。如果我的json包含with
“…”意味着它将结束一次。我必须做什么？如果我这样做，我该如何逃逸？
mysqli\u real\u escape\u string（{“apiVersion”：……）
；这也是一个错误。我使用php功能存储我的json数据。对于任何
语法错误
都可以。但在我完成
json\u解码（$data）之后
它什么也不显示。@Ranjith做一件事。首先使用
JSON\u decode
解码JSON，然后使用
JSON\u encode
使用可用的JSON常量对其进行编码。我的JSON内容中也包含“”（单引号）。因此字符串中断，并给出错误。