Php MySQL使用不同的WHERE子句进行多次计数并查看结果

我试图从我的订单表中获取：每个客户在一周内下的订单数量，然后在下一周再做一次计数，然后再做一次，再做一次，等等

我正在使用COUNT，但它不断返回一个空结果

这是我的问题

SELECT `uid`, (SELECT COUNT(`uid`) FROM `orders` WHERE `order_timestamp` > '1476707688' and `order_timestamp` < '1476189288') as 'number1',
       (SELECT COUNT(`uid`) FROM `orders` WHERE `order_timestamp` > '1476189288' and `order_timestamp` < '1475584488') as 'number2',
       (SELECT COUNT(`uid`) FROM `orders` WHERE `order_timestamp` > '1475584488' and `order_timestamp` < '1474979688') as 'number3'
FROM `orders` ORDER BY `uid` ASC

结果如下所示：

我知道一周内有多个客户下了多个订单

你怎么做这个查询？ 将带回客户在该时间段内的订单数量的查询

---

干杯，

你能试一下吗

SELECT * FROM {table} WHERE date > DATE_SUB(NOW(), INTERVAL 1 DAY) ORDER BY uid DESC;        
SELECT * FROM {table}WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK) ORDER BY uid DESC;
SELECT * FROM {table}WHERE date > DATE_SUB(NOW(), INTERVAL 1 MONTH) ORDER BY uid DESC;

---

你能试一下吗

SELECT * FROM {table} WHERE date > DATE_SUB(NOW(), INTERVAL 1 DAY) ORDER BY uid DESC;        
SELECT * FROM {table}WHERE date > DATE_SUB(NOW(), INTERVAL 1 WEEK) ORDER BY uid DESC;
SELECT * FROM {table}WHERE date > DATE_SUB(NOW(), INTERVAL 1 MONTH) ORDER BY uid DESC;

---

只需使用条件聚合：

SELECT `uid`,
       SUM(`order_timestamp` > '1476707688' and `order_timestamp` < '1476189288') as number1,
       SUM(`order_timestamp` > '1476189288' and `order_timestamp` < '1475584488') as number2,
       SUM(`order_timestamp` > '1475584488' and `order_timestamp` < '1474979688') as number3
FROM `orders`
GROUP BY `uid` ASC;

---

注意：这是按uid聚合的，因此每个uid将有一行，而不是每个订单。这似乎是明智之举。

只需使用条件聚合：

SELECT `uid`,
       SUM(`order_timestamp` > '1476707688' and `order_timestamp` < '1476189288') as number1,
       SUM(`order_timestamp` > '1476189288' and `order_timestamp` < '1475584488') as number2,
       SUM(`order_timestamp` > '1475584488' and `order_timestamp` < '1474979688') as number3
FROM `orders`
GROUP BY `uid` ASC;

---

注意：这是按uid聚合的，因此每个uid将有一行，而不是每个订单。这似乎是明智之举。

order\u timestamp>'1475584488'和order\u timestamp<'1474979688'`您确定这将返回一个值吗？有什么能超过1475年吗。。。还不到1474？是的，那是新手犯的错误！order_timestamp>'1475584488'和order_timestamp<'1474979688'`您确定这将返回一个值吗？有什么能超过1475年吗。。。还不到1474？是的，那是新手犯的错误！这就是我想要的！谢谢你，伙计。还有，我本来就把大于，小于。。。所以正好相反但这带来了我需要的结果。谢谢这就是我想要的！谢谢你，伙计。还有，我本来就把大于，小于。。。所以正好相反但这带来了我需要的结果。谢谢你能说得更准确些吗？你的意图是什么？你面临着什么问题？你能说得更准确些吗？你的意图是什么？你面临什么问题？