Php 通过ajax jquery上传文件
我试图用jQueryAjax上传文件输入,但没有刷新页面。 我的html表单是Php 通过ajax jquery上传文件,php,jquery,ajax,Php,Jquery,Ajax,我试图用jQueryAjax上传文件输入,但没有刷新页面。 我的html表单是 <form name="uploadform" id="uploadform" method="post" enctype="multipart/form-data"> <div name="profileBiodata" id="profileBiodata" style="display:none"> <input type="file" id="file
<form name="uploadform" id="uploadform" method="post" enctype="multipart/form-data">
<div name="profileBiodata" id="profileBiodata" style="display:none">
<input type="file" id="file" name="file">
<input type="submit" id="submit" value="Upload" >
</div>
</form>
我的php页面是
<?php
if (isset($_POST['filename']))
{
echo '{"status" : "success"}';
}
?>
但我收到了输出警报
你离线了\n请检查您的网络。
如何解决此问题。请任何人帮助。提前感谢它工作正常。下面是修改后的代码 HTML表单
<form name="uploadform" id="uploadform" method="post" enctype="multipart/form-data">
<div name="profileBiodata" id="profileBiodata">
<input type="file" id="file" name="file">
<input type="submit" id="submit" value="Upload" >
</div>
</form>
ProfileBiodataUpload.php
<?php
if (isset($_POST['filename']))
{
echo '{"status" : "success"}';
}
?>
$(document).ready(function() {
// process the form
$('#uploadform').submit(function() {
var filename = $("#file").val();
$.ajax({
url: 'ProfileBiodataUpload.php',
dataType: 'json',
type: 'POST',
data: {"op": "upload", "filename": filename},
success: function(response) {
if (response.status == "success") {
alert("file exists");
}
else if (response.status == "failure")
{
alert("file not exists");
}
},
error: function(x, e) {
if (x.status === 0) {
alert('You are offline!!\n Please Check Your Network.');
} else if (x.status === 404) {
alert('Requested URL not found.');
} else if (x.status === 500) {
alert('Internel Server Error - Please try after relogin to the application');
} else if (e === 'parsererror') {
alert('Parsing JSON Request failed.');
} else if (e === 'timeout') {
alert('Request Time out.');
} else {
alert('Unknow Error.\n' + x.responseText);
}
}
});
return false;
});
});
<?php
if (isset($_POST['filename']))
{
echo '{"status" : "success"}';
}
?>