Php Idgenerator laravel 8，如何修复异常；表字段类型为bigint，但前缀为string"；

为什么总是出现此消息？ 即使我想用两个点做一个id，比如=190772.2021.00000001 不能添加“.”（点）这样只能添加1个点只有1907722021.00000001 factory.php

namespace Database\Factories;

use App\Models\Anggota;
use Illuminate\Database\Eloquent\Factories\Factory;
use App\Models\User;
use Haruncpi\LaravelIdGenerator\IdGenerator;

class AnggotaFactory extends Factory
{
    /**
     * The name of the factory's corresponding model.
     *
     * @var string
     */
    protected $model = Anggota::class;

    /**
     * Define the model's default state.
     *
     * @return array
     */
    public function definition()
    {
        $tgl = $this->faker->date;

        return [
            'id_user' => User::factory(),
            'no_anggota' => IdGenerator::generate([
                    'table' => 'anggotas', 
                    'length' => 19, 
                    'prefix' => date('dmy', strtotime($tgl)).date('.Y.')
                ]),
            'nama_lengkap' => $this->faker->name,
            'tempat_lahir' => $this->faker->cityPrefix,
            'tanggal_lahir' => $tgl,
            'nama_instansi' => $this->faker->word,
        ];
    }
}

文件迁移

use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateAnggotasTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('anggotas', function (Blueprint $table) {
            $table->id();
            $table->unsignedBigInteger('id_user')->unique();
            $table->string('no_anggota');
            $table->string('nama_lengkap');
            $table->string('tempat_lahir');
            $table->date('tanggal_lahir');
            $table->string('nama_instansi');
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('anggotas');
    }
}

而模式数据库中的列“no_anggota”的类型为“string”，但显示为“table field type为bigint，prefix为string”

如何求解，使结果=190772.2021.00000001

帮助我，谢谢

软件包默认使用表的

id

列。根据您的需要，您还必须通过

字段

您所需的输出：190772.2021.00000001（长度20，带两个点）

解决方案：只需通过
'field'=>'no_anggota'
和
'length'=>20

$tgl = $this->faker->date;

$idConfig = [
    'table' => 'anggotas',
    'field' => 'no_anggota',
    'length' => 20,
    'prefix' => date('dmy', strtotime($tgl)).date('.Y.')
];

return [
    'id_user' => User::factory(),
    'no_anggota' => IdGenerator::generate($idConfig),
    'nama_lengkap' => $this->faker->name,
    'tempat_lahir' => $this->faker->cityPrefix,
    'tanggal_lahir' => $tgl,
    'nama_instansi' => $this->faker->word,
];

谢谢，它的工作：）