Php 操纵美元和美元的交易价值；分

让我们限制值用户可以输入+使用函数正确打印结果

<input name="dollar"...
<input name="cent"...

<?PHP

if ( !is_numeric($_POST['dollar'])) { return; }
if ( !is_numeric($_POST['cent'])) { return; }

$total = $_POST['dollar'].".".$_POST['cent'];

您可以使用一个名为的函数。在这种情况下，解决方案是：

<input name="dollar"...
<input name="cent"...

<?php
  //Dollar is an integer above zero
  $dollar = max(0, intval($_POST['dollar'])); 

  //Cent is an integer between 0 and 99
  $cent = min(99, max(0, intval($_POST['cent']))); 

  //Version to place into logs
  $total = $dollar.".".$cent;

  // Added from another answer to keep everything together

  //Set the local to parse monetary values correctly
  setlocale(LC_MONETARY,"en_US");

  //Get correct monetary value with 2 decimal place and **$** sign
  //Version to print
  $total = money_format("%.2n", $total);

或者更好：

$total = money_format($_POST['dollar'].".".$_POST['cent']);

希望有帮助。
祝你好运
 为什么用户不能在2030年为$u POST['dollar']和$u POST['cent']分别输入6和6？我的日志会显示2030.06而不是2030.6不必担心返回，它只是停止脚本并将错误消息返回到视图看起来像是一项工作，或者可能是我现在所做的工作的副本是乘以100--->203.06*100
$dollar = filter_input(INPUT_POST, "dollar");
$cent = filter_input(INPUT_POST, "cent");

//Set the local to parse monetary values correctly
setlocale(LC_MONETARY,"en_US");

//Get correct monetary value with 2 decimal place and **$** sign
$total = money_format("%.2n", $dollar.'.'.$cent);