Php flock()是否仅适用于当前方法?
Php flock()是否仅适用于当前方法?,php,methods,file-locking,flock,Php,Methods,File Locking,Flock,flock()函数是否仅在与代码执行相同的方法中使用时才起作用 例如,在以下代码中,锁定成功: public function run() { $filePointerResource = fopen('/tmp/lock.txt', 'w'); if (flock($filePointerResource, LOCK_EX)) { sleep(10); } else { exit('Could not get lock!'); }
flock()
函数是否仅在与代码执行相同的方法中使用时才起作用
例如,在以下代码中,锁定成功:
public function run()
{
$filePointerResource = fopen('/tmp/lock.txt', 'w');
if (flock($filePointerResource, LOCK_EX)) {
sleep(10);
} else {
exit('Could not get lock!');
}
}
public function run()
{
if ($this->lockFile()) {
sleep(10);
} else {
exit('Could not get lock!');
}
}
private function lockFile()
{
$filePointerResource = fopen('/tmp/lock.txt', 'w');
return flock($filePointerResource, LOCK_EX);
}
但是,在以下代码中,锁定不成功:
public function run()
{
$filePointerResource = fopen('/tmp/lock.txt', 'w');
if (flock($filePointerResource, LOCK_EX)) {
sleep(10);
} else {
exit('Could not get lock!');
}
}
public function run()
{
if ($this->lockFile()) {
sleep(10);
} else {
exit('Could not get lock!');
}
}
private function lockFile()
{
$filePointerResource = fopen('/tmp/lock.txt', 'w');
return flock($filePointerResource, LOCK_EX);
}
我还没有看到任何关于这方面的文档,所以我对这种行为感到困惑。我使用的是php版本5.5.35。我认为基于类的尝试的问题是,当
lockFile
方法完成$filePointerResource
时,超出了范围,这可能就是释放锁的原因
这是可行的,哪一种支持这一理论
<?php
class test {
public function run()
{
$fp = fopen('lock.txt', 'w');
if ($this->lockFile($fp)) {
echo 'got a lock'.PHP_EOL;
sleep(5);
}
/*
* Not going to do anything as the attempt to lock EX will
* block until a lock can be gained
else {
exit('Could not get lock!'.PHP_EOL);
}
*/
}
private function lockFile($fp)
{
return flock($fp, LOCK_EX);
}
}
$t = new test();
$t->run();
哇,这就解释了。非常感谢。