Php 将Json数组转换为简单Json
我有json数据Php 将Json数组转换为简单Json,php,json,laravel,Php,Json,Laravel,我有json数据 {"@attributes":{"titleID":"24151"},"artist":"ALMKLAUSI & SPECKTAKEL","title":"Mama Laudaaa","label":"Xtreme Sound"} 但我需要这样的数据 {titleID":"24151","artist":"ALMKLAUSI & SPECKTAKEL","title":"Mama Laudaaa","label":"Xtreme Sound"} 您可以使用f
{"@attributes":{"titleID":"24151"},"artist":"ALMKLAUSI & SPECKTAKEL","title":"Mama Laudaaa","label":"Xtreme Sound"}
但我需要这样的数据
{titleID":"24151","artist":"ALMKLAUSI & SPECKTAKEL","title":"Mama Laudaaa","label":"Xtreme Sound"}
您可以使用
foreach
循环来获取此输出
代码:
<?php
$str ='{"@attributes":{"titleID":"24151"},"artist":"ALMKLAUSI & SPECKTAKEL","title":"Mama Laudaaa","label":"Xtreme Sound"}';
$arr = json_decode($str,true);
$final_arr= array();
foreach($arr as $key=>$value){
if($key== '@attributes'){
$key = key($value);
$value= $value[key($value)];
}
$final_arr[$key]= $value;
}
$final_str = json_encode($final_arr);
print_r($final_str);
exit;
{"titleID":"24151","artist":"ALMKLAUSI & SPECKTAKEL","title":"Mama Laudaaa","label":"Xtreme Sound"}
对你有好处,你试过什么吗?是的,我试过了,但没什么效果,所以我来了。也许任何人都可以帮助我。也许可以分享你迄今为止所做的一切!如果我们在jquery中有相同的东西,请您帮助我。实际上我是新的,正在处理LaravelAPI.success:function(data){var array=$.map(data,function(item){return{label:item[autoType],value:item[autoType],数据:item}});//console.log(数组);response(数组)}