如何使用php的强大功能和魔力在数据库中输入或插入一个或多个产品的名称?
我正在尝试输入一个名称和更多的产品。这里的场景是当我 输入名称:uuuuuuuuuuuuuuuuuuuuuuuuuuuuu产品:______________ 产品名称:uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 它将被插入数据库,并显示如下: Johnny | Iphone Johnny | Windows Phone 约翰尼| Iphone Johnny | Windows Phone 这是我的密码:如何使用php的强大功能和魔力在数据库中输入或插入一个或多个产品的名称?,php,for-loop,mysqli,foreach,Php,For Loop,Mysqli,Foreach,我正在尝试输入一个名称和更多的产品。这里的场景是当我 输入名称:uuuuuuuuuuuuuuuuuuuuuuuuuuuuu产品:______________ 产品名称:uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 它将被插入数据库,并显示如下: Johnny | Iphone Johnny | Windows Phone 约翰尼| Iphone Johnny | Windows
<form action="" method="POST">
<table>
<tr>
<td>Name</td>
<td><input type="text" name="name_txt[]" /></td>
</tr>
<tr>
<td>Product</td>
<td><input type="text" name="product_name_txt[]" /></td>
</tr>
<tr>
<td>Product</td>
<td><input type="text" name="product_name_txt[]" /></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="add" />
<input type="reset" name="submit" value="clear" /></td>
</tr>
</table>
</form>
<?php
if(isset($_POST['submit']))
{
include 'db.php';
foreach($_POST['product_name_txt'] as $row => $value){
$name=$_POST['name_txt'][$row];
$product=$_POST['product_name_txt'][$row];
$sql = "INSERT INTO request(p_name, product_name) VALUES ('$name','$product')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}
}
?>
名称
产品
产品
首先,由于只有一个名称,您应该使用name\u txt
而不是name\u txt[]
。其次,对于您的产品,请使用infrade()
函数以字符串连接数组元素,然后执行INSERT
操作
改变这个
<td><input type="text" name="name_txt[]" /></td>
到
您的表单处理过程如下所示:
if(isset($_POST['submit'])){
include 'db.php';
$name=$_POST['name_txt'];
$products = implode(" ", $_POST['product_name_txt']);
$sql = "INSERT INTO request(p_name, product_name) VALUES ('$name','$products')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}
if(isset($_POST['submit']){
包括“db.php”;
$name=$\u POST['name\u txt'];
$products=内爆(“,$U POST['product\U name\U txt']);
$sql=“在请求(p_名称、产品名称)值(“$name”、“$products”)中插入”;
if(mysqli_查询($conn,$sql)){
echo“新记录创建成功”;
}否则{
echo“Error:”.$sql.
“.mysqli_Error($conn);
}
}
以下是参考资料:
以上答案是正确的,但您只需修改即可
$name=$\u POST['name\u txt'];
$products=$\u POST['product\u name\u txt'];
foreach(产品为$value){
$sql=“在请求(p_名称、产品_名称)中插入值(“$name”、“$value”)”;
if(mysqli_查询($conn,$sql))
{
回显“已成功创建新记录”;}
否则{
echo“Error:”.$sql.
“.mysqli_Error($conn);
}
}
您的代码有错误吗?逻辑错误请查看链接图像[link]()
if(isset($_POST['submit'])){
include 'db.php';
$name=$_POST['name_txt'];
$products = implode(" ", $_POST['product_name_txt']);
$sql = "INSERT INTO request(p_name, product_name) VALUES ('$name','$products')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}
<td><input type="text" name="name_txt" /></td>
$name = $_POST['name_txt'];
$products = $_POST['product_name_txt'];
foreach($products as $value){
$sql = "INSERT INTO request(p_name, product_name) VALUES ('$name','$value')";
if (mysqli_query($conn, $sql))
{
echo "New record created successfully"; }
else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}