PHP检查字符串中是否至少包含两个特定单词_Php_Preg Match

PHP检查字符串中是否至少包含两个特定单词

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PHP检查字符串中是否至少包含两个特定单词,php,preg-match,Php,Preg Match,我正在使用preg\u match检查字符串中是否有特定的单词： $string = 'This string contains a few words that are in an array!'; $arr = ['string', 'few', 'words']; if(preg_match('['.implode('|', $arr).']', $string)){ //do something if there is at least one word from the ar

我正在使用

preg\u match

检查字符串中是否有特定的单词：

$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];

if(preg_match('['.implode('|', $arr).']', $string)){
    //do something if there is at least one word from the array inside that string
}

这是相当不错的工作，但它将返回真，如果有至少一个字，我需要它返回真，如果有至少两个字从数组中的字符串

这可以一步完成吗？如果没有，我应该从这里走哪条路来获得这个结果

谢谢D

您可以使用preg\u match\u all进行此操作

$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];
$count = preg_match_all('['.implode('|', $arr).']', $string); // Returns 3

您可以使用preg_match_all进行此操作

$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];
$count = preg_match_all('['.implode('|', $arr).']', $string); // Returns 3

如果您不关心精确匹配，则选择的答案是正确的。如果要匹配精确的单词，则需要使用单词边界

\b

以下是一个例子：

$arr = ['string', 'few', 'words'];

preg_match_all('#\b('.implode('|', $arr).')\b#', $string, $wordsFound);

$wordsFound = array_unique($wordsFound[0]);

if(count($wordsFound) >= 2){
    echo "Matched";
}else{
    echo "Not matched";
}


Input: $string = 'This string contains a few words that are in an array!';
Output: Matched (3 founds)

Input: $string = 'This string222 contains a few words that are in an array!';
Output: Matched (2 founds)

Input: $string = 'This string222 contains a few23 words that are in an array!';
Output: Not Matched (1 found)

Input: $string = 'This string contains a string words that are in an array!';
Output: Matched (2 founds)

Input: $string = 'This string contains a string string that are in an array!';
Output: Not Matched (1 found)

如果您不关心精确匹配，则选择的答案是正确的。如果要匹配精确的单词，则需要使用单词边界

\b

以下是一个例子：

$arr = ['string', 'few', 'words'];

preg_match_all('#\b('.implode('|', $arr).')\b#', $string, $wordsFound);

$wordsFound = array_unique($wordsFound[0]);

if(count($wordsFound) >= 2){
    echo "Matched";
}else{
    echo "Not matched";
}


Input: $string = 'This string contains a few words that are in an array!';
Output: Matched (3 founds)

Input: $string = 'This string222 contains a few words that are in an array!';
Output: Matched (2 founds)

Input: $string = 'This string222 contains a few23 words that are in an array!';
Output: Not Matched (1 found)

Input: $string = 'This string contains a string words that are in an array!';
Output: Matched (2 founds)

Input: $string = 'This string contains a string string that are in an array!';
Output: Not Matched (1 found)

如果您的要求是知道字符串中至少存在2个所需单词，那么您需要小心。如果字符串中有两个相同的单词，如果只使用

preg\u match\u all

搜索发生的情况，很容易得到误报

这将报告3，即所有3个单词都出现在草堆中

$string = 'This string contains a string and a few other words!';
$finds = ['string', 'few', 'words'];
$findCount = 0;

foreach ($finds as $find) {
    if ( strpos($string, $find) !== false ) $findCount++;
}
echo $findCount;

如果使用此字符串，它将报告2

$string = 'This string contains a string and a other words!';

最重要的是，如果您使用包含单词

string

的字符串两次，而不是所需单词中的两个，则只报告1

$string = 'This string contains a string and other stuff!';