Php 合并并用两个表SQL的名称替换表id

表客户：

+----+------------+
| id | text       |
+----+------------+
| 33 | name1      | 
| 34 | name2      | 
| 35 | name3      | 
| 36 | name4      | 
+----+------------+

表顺序：

+----+--------+------------+----------+
| id |  cid   |  ordername |  colors  |
+----+--------+------------+----------+
|  8 |   34   |    name    |    5     |        
+----+--------+------------+----------+

一次查询是否可能得到此结果

+----+--------+------------+----------+
| id |  cid   |  ordername |  colors  |
+----+--------+------------+----------+
|  8 | name1  |    name    |    5     |        
+----+--------+------------+----------+

这是你怎么做的

   select o.`id`, `text` as cid , `ordername`, `colors` from orders o
   inner join customers c
   on  c.id = o.cid 

输出：

   ID   CID     ORDERNAME   COLORS
   8    name2   name              5

---

什么是开斋节？并且cid在结果中不是name2？使用联接和别名，假设

name1

应该是

name2