Php MySQL-返回表中的行数

我不太擅长PHP，但我知道一些其他类似的语言

现在我要做的是得到一个表中有多少行。这是我的密码

$result = mysql_query("SELECT COUNT(*) FROM list");
$num_rows = mysql_num_rows($result);
echo $num_rows;

现在这段代码返回1，实际上是3。为什么呢？ 谢谢您的帮助。

尝试以下方法：

$result = mysql_query("SELECT COUNT(*) FROM list");
$num_rows = mysql_fetch_object($result);
print_r($num_rows);

$result = mysql_query("select count(*) FROM list");
$row = mysql_fetch_array($result);
echo $row[0];

注意：Mysql_*函数已弃用。因此不建议使用。

<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$result = mysqli_query($con,"SELECT COUNT(*) as total_row FROM list");

echo "<table border='1'>
<tr>
<th>total_row</th>
</tr>";

while($row = mysqli_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['total_row'] . "</td>";
  echo "</tr>";
  }
echo "</table>";

mysqli_close($con);
?>

您应该这样做：

$result = mysql_query("SELECT * FROM list");
$num_rows = mysql_num_rows($result);
echo $num_rows;

如果要通过

COUNT

获取总行数，可以执行以下操作：

$result = mysql_query("SELECT COUNT(*) FROM list");
$num_rows = mysql_fetch_object($result);
print_r($num_rows);

$result = mysql_query("select count(*) FROM list");
$row = mysql_fetch_array($result);
echo $row[0];

检查这个

$result = mysql_fetch_array(mysql_query("SELECT COUNT(*) as count FROM list"));
echo $result['count'];

---

它返回单个列中的行数计数，然后仅返回1

请参阅：

仅更改您的查询

$result = mysql_query("SELECT * FROM list");
$num_rows = mysql_num_rows($result);
echo $num_rows;

---

它返回一行，因为下面的查询只返回一个值，即行数

$result = mysql_query("SELECT COUNT(*) FROM list");

我认为这应该有帮助：

$result = mysql_query("SELECT COUNT(*) FROM list");
$num_rows = $result->fetchColumn();
echo $num_rows;