Php 如何仅在子菜单后获得下划线（不在父菜单后）

我在家长菜单后面画了下划线。我想在父菜单后加下划线，但如果有子菜单，我想在子菜单后加下划线。但问题是下划线后子菜单的打印。怎么办？有人能帮我吗

 <?php 
    foreach($menus as $menu) {
        if($menu->menu_item_parent == 0) { ?>
                <a id="fluid" href="#"><?php echo $menu->title ?></a>
                <hr class="divider">
                <?php }
                 
        else{ ?>
                <div id="parent-sub">
                        <a id="submenu" href="#"><?php echo $menu->title ?></a>
                    </div>
                
            
        <?php } 
    }  ?>   

这将帮助您确定项目是否有子项

 Array
(
  [0] => WP_Post Object
    (
        [ID] => 712
        [post_author] => 1
        [post_date] => 2021-05-28 10:17:47
        [post_date_gmt] => 2021-05-28 07:34:55
        [post_content] =>  
        [post_title] => 
        [post_excerpt] => 
        [post_status] => publish
        [comment_status] => closed
        [ping_status] => closed
        [post_password] => 
        [post_name] => 712
        [to_ping] => 
        [pinged] => 
        [post_modified] => 2021-05-28 10:17:47
        [post_modified_gmt] => 2021-05-28 10:17:47
        [post_content_filtered] => 
        [post_parent] => 0
        [guid] => http://localhost/fluid/?p=712
        [menu_order] => 1
        [post_type] => nav_menu_item
        [post_mime_type] => 
        [comment_count] => 0
        [filter] => raw
        [db_id] => 712
        [menu_item_parent] => 0
        [object_id] => 24
        [object] => page
        [type] => post_type
        [type_label] => Page
        [url] => http://localhost/fluid/fluid-difference/
        [title] => Fluid Difference
        [target] => 
        [attr_title] => 
        [description] => 
        [classes] => Array
            (
                [0] => 
            )

        [xfn] => 
    )

if ( $menu->has_children ) {
//has children
} else {
//does not have children
}