php-使用preg_replace允许负十进制

我在变量中有输入掩码，如

200.000,54

这是我的php代码

<?php

class MoneyHelper
{
    public function getAmount($money)
    {
        $cleanString = preg_replace('/([^0-9\.,])/i', '', $money);
        $onlyNumbersString = preg_replace('/([^0-9])/i', '', $money);

        $separatorsCountToBeErased = strlen($cleanString) - strlen($onlyNumbersString) - 1;

        $stringWithCommaOrDot = preg_replace('/([,\.])/', '', $cleanString, $separatorsCountToBeErased);
        $removedThousandSeparator = preg_replace('/(\.|,)(?=[0-9]{3,}$)/', '',  $stringWithCommaOrDot);

        //return (float) str_replace(',', '.', $removedThousandSeparator);

        return [
          'cleanString' => $cleanString,
          'onlyNumbersString' => $onlyNumbersString,
          'separatorsCountToBeErased' => $separatorsCountToBeErased,
          'stringWithCommaOrDot' => $stringWithCommaOrDot,
          'removedThousandSeparator' => $removedThousandSeparator,
          'result' => (float) str_replace(',', '.', $removedThousandSeparator)

        ];

    }
}


$obj = new MoneyHelper;
echo var_dump($obj->getAmount('200.000,54')) ;

在我用负数测试这段代码之前，一切都很好。 比如说

-200.000,54

那么结果还是一样的,

array (size=6)
  'cleanString' => string '200.000,54' (length=10)
  'onlyNumbersString' => string '20000054' (length=8)
  'separatorsCountToBeErased' => int 1
  'stringWithCommaOrDot' => string '200000,54' (length=9)
  'removedThousandSeparator' => string '200000,54' (length=9)
  'result' => float 200000.54

我怎样才能得到结果中的负数？ 请告知

更新

你还没有告诉我们你想要的确切产量

---

我需要：

'result'=>float-200000.54

您只需要将负号添加到求反字符类中。我可能还会做一些其他的调整

代码段：（）

输出：

array(6) {
  ["cleanString"]=>
  string(11) "-200.000,54"
  ["onlyNumbersString"]=>
  string(9) "-20000054"
  ["separatorsCountToBeErased"]=>
  int(1)
  ["stringWithCommaOrDot"]=>
  string(10) "-200000,54"
  ["removedThousandSeparator"]=>
  string(10) "-200000,54"
  ["result"]=>
  float(-200000.54)
}

---

十进制是

/^-？[0-9]+（？：\.[0-9]+）？$/

或

/^-？\d+（？：\.\d+）$/

可选

-

然后是一个数字，然后是可选的

和一些其他数字。

^

开始和

$

结束确保您不会部分匹配，例如

123foo

至于问题，您至少在这里将其剥离2倍

preg\u replace（'/（[^0-9\，]））/我的“

没有减号，所以它被删除了，下一行的另一个时间。

不需要在字符类中转义。请查看我的更新

$cleanString = preg_replace('/[^\d.,-]/', '', $money);
$onlyNumbersString = preg_replace('/[^\d-]/', '', $money);

$separatorsCountToBeErased = strlen($cleanString) - strlen($onlyNumbersString) - 1;

$stringWithCommaOrDot = preg_replace('/[,.]/', '', $cleanString, $separatorsCountToBeErased);
$removedThousandSeparator = preg_replace('/[.,](?=\d{3,}$)/', '',  $stringWithCommaOrDot);

array(6) {
  ["cleanString"]=>
  string(11) "-200.000,54"
  ["onlyNumbersString"]=>
  string(9) "-20000054"
  ["separatorsCountToBeErased"]=>
  int(1)
  ["stringWithCommaOrDot"]=>
  string(10) "-200000,54"
  ["removedThousandSeparator"]=>
  string(10) "-200000,54"
  ["result"]=>
  float(-200000.54)
}