Php laravel 5.4未定义的属性：stdClass:：$id

我有两个模特艺术家和两首歌，它们有一对多的关系，一个艺术家可以有多首歌。这首歌属于一位艺术家

$artists = DB::table('artists')->join('songs', 'artists.id', '=', 'songs.artist_id')->select('artists.*, songs.id, songs.title, songs.artist_id, songs.week_hits, songs.created_at')
            ->SELECT(DB::raw('sum(songs.week_hits) as WEEKHITS'))->groupBy('songs.artist_id')->orderBy('WEEKHITS', 'DESC')->take(7)->get();
 return return view('front.home', compact('videos', 'songs', 'artists', 'played', 'uploads', 'albums'));

这是我的控制器代码。如你所见，我添加了所有艺人歌曲周点击率，并按歌曲进行分组。艺人id

这是我的观点

 @foreach($artists as $artist)
            <div class="artist-grid">
                <div class="art-img">
                    <a href="{{route('artist',['id' => $artist->id, 'slug' => $artist->slug])}}">
                        <img  src="image/small/{{$artist->image}}">
                    </a>
                </div>
                <div class="name">
                    <h3>{{$artist->name}}</h3>
                </div>
            </div>
             @endforeach

但当我添加（$artists）时，这就是输出

Collection {#293 ▼
  #items: array:4 [▼
    0 => {#307 ▼
      +"WEEKHITS": "39"
    }
    1 => {#292 ▼
      +"WEEKHITS": "9"
    }
    2 => {#278 ▼
      +"WEEKHITS": "4"
    }
    3 => {#308 ▼
      +"WEEKHITS": "1"
    }
  ]
}

---

非常感谢您的帮助。

请按如下方式尝试返回视图：

return view('front.home')->with($artists, compact('artists'));

编辑 要传递多个变量，有许多解决方案。比如：

return view('front.home')->with(compact('videos', 'songs', 'artists', 'played', 'uploads', 'albums'));

---

请查看您的查询，您还必须在查询的select（）选项中选择id

$artists = DB::table('artists')->join('songs', 'artists.id', '=', 'songs.artist_id')->select('artists.*, songs.id, songs.title, songs.artist_id, songs.week_hits, songs.created_at')
            ->SELECT(DB::raw('sum(songs.week_hits) as WEEKHITS','artists.id as id'))->groupBy('songs.artist_id')->orderBy('WEEKHITS', 'DESC')->take(7)->get();

或

---

问题似乎出在您的查询中，您选择了两次，第二个select语句覆盖了第一个语句，这就是为什么您只得到“WEEKHITS”

---

组合两个select语句。

很抱歉，我没有在上面提到，我不仅发送$artists变量以查看，还有另一个视图，返回视图（'front.home'，compact（'videos'，'songs'，'artists'，'played'，'uploads'，'albums'）；您可以使用多个

和
发送多个变量。查看我更新的naswer@mahamoudmahamedyou dd（）美元美术师收藏值，并向我们显示单个输入的结果吗？这是我dd（$美术师）变量的时候。收藏{#293▼   #项目：阵列：4[▼     0 => {#307 ▼       +“WEEKHITS”：“39”}1=>{#292▼       +“WEEKHITS”：“9”}2=>{#278▼       +“WEEKHITS”：“4”}3=>{308▼       +“WEEKHITS”：“1”}]}除了他们，我仍然没有做任何改变。我认为问题在于这一部分。由于您可以在foreach（）中找到id route$artist->idplease dd（）的属性，因此您可以看到$artist对象的实际情况。
$artists = DB::table('artists')->join('songs', 'artists.id', '=', 'songs.artist_id')->select('artists.*, songs.id, songs.title, songs.artist_id, songs.week_hits, songs.created_at')
            ->SELECT(DB::raw('sum(songs.week_hits) as WEEKHITS','artists.id as id'))->groupBy('songs.artist_id')->orderBy('WEEKHITS', 'DESC')->take(7)->get();

  $artists = DB::table('artists')->join('songs', 'artists.id', '=', 'songs.artist_id')->select('artists.*, songs.id, songs.title, songs.artist_id, songs.week_hits, songs.created_at')
                ->SELECT(DB::raw('sum(songs.week_hits) as WEEKHITS','artists.*'))->groupBy('songs.artist_id')->orderBy('WEEKHITS', 'DESC')->take(7)->get();