Php Mysql-选择具有相同值的多行

我有一个名为“data”的表和一些列：
用户、单位、价格、折扣、说明

 -----   -----  ------  ---------   ----------- 
| user | unit |  price | discount | description |
 -----   -----  ------  ---------   -----------
| test | unit |  100   |    50    |     des     |
-----   -----  -------   --------   -----------
| test2| unit2 |  200  |    20    |     des     |
 -----   -----  -----    --------   -----------

所以这只是第一排。我想让他们两个都这样：

{"result":[{"user":"test","unit":"unit","price":"100","discount":"50"}]}
{"result2":[{"user":"test2","unit":"unit2","price":"200","discount":"20"}]}

---

因此将有2个数组。

您需要编写一个包含调用

mysqli\u fetch\u assoc（）

的循环。迭代时，存储数据行

while($row = mysqli_fetch_assoc($r)){
    array_push($result, array(
         "user" => $row['user'],
         "unit" => $row['unit'],
         "price" => $row['price'],
         "discount" => $row['discount']
         )
     );
}

或者，如果替换

选择

子句中的

*

来指定所需的行，则可以使用

mysqli\u fetch\u assoc（）

手动页面上投票最多的注释

for ($result = []; $row = mysqli_fetch_assoc($r); $result[] = $row);

---

这个紧凑的单行程序将把您的结果集转换成一个多维数组，该数组的结构与前面的代码块相同，而不需要迭代的

array\u push（）

函数调用。

首先，您的查询是开放的，可以使用sql注入

<?php 
 if($_SERVER['REQUEST_METHOD']=='GET'){
 $id  = $_GET['id'];
 require_once('dbConnect.php');
 $sql = "SELECT * FROM data WHERE description='".$id."'";
 $r = mysqli_query($con,$sql);
 $result = array();
 while ($res = mysqli_fetch_assoc($r)){
    $aRaw["user"] = $res['user'];
    $aRaw["unit"] = $res['unit'];
    $aRaw["price"] = $res['price'];
    $aRaw["discount"] = $res['discount'];
    $result[] = $aRaw;
 }
 );
 echo json_encode(array("result"=>$result));
 mysqli_close($con);
 }

那么你的代码看起来是这样的

编辑：我的原始答案不完整，因为我没有测试。下面是我的更正答案

<?php 
 if($_SERVER['REQUEST_METHOD']=='GET'){
 $id  = $_GET['id'];
 require_once('dbConnect.php');
 $sql = "SELECT * FROM data WHERE description=?";
 $stmt = mysqli_prepare($con,$sql);
 $stmt->bind_param("s", $id);
 $stmt->execute(); //originally I combined this and next line, it was incorrect
 if ($result = $stmt->get_result()){
    //originally I used wrong method below
    while($row = $result->fetch_assoc()) {
            $myArray[] = $row;
    }
    //uncomment below if you're sending response as json responese
    //header('Content-Type: application/json');
    echo json_encode($myArray);
}

$result->close();

警告：mysqli_fetch_assoc（）期望参数1是mysqli_result，在第9行{“result”：[]}@NikitaIvanov I修复了它致命错误：未捕获错误：在/storage/h7/538/1215538/public_html/UserLogin.php中调用布尔值上的成员函数fetch_array（）在第11行输入/storage/h7/538/1215538/public_html/UserLogin.php。我已经更新了我的答案，很抱歉我最初发布了错误警告：您的代码易受攻击。请阅读以了解更多关于如何预防它的信息。@Pang我们谈论的是获取所有记录，而不是如何处理SQL注入，这是她的工作，显然她在这方面是新手，所以不要把事情复杂化。
<?php 
 if($_SERVER['REQUEST_METHOD']=='GET'){
 $id  = $_GET['id'];
 require_once('dbConnect.php');
 $sql = "SELECT * FROM data WHERE description='".$id."'";
 $r = mysqli_query($con,$sql);
 $result = array();
 while ($res = mysqli_fetch_assoc($r)){
    $aRaw["user"] = $res['user'];
    $aRaw["unit"] = $res['unit'];
    $aRaw["price"] = $res['price'];
    $aRaw["discount"] = $res['discount'];
    $result[] = $aRaw;
 }
 );
 echo json_encode(array("result"=>$result));
 mysqli_close($con);
 }

<?php 
 if($_SERVER['REQUEST_METHOD']=='GET'){
 $id  = $_GET['id'];
 require_once('dbConnect.php');
 $sql = "SELECT * FROM data WHERE description=?";
 $stmt = mysqli_prepare($con,$sql);
 $stmt->bind_param("s", $id);
 $stmt->execute(); //originally I combined this and next line, it was incorrect
 if ($result = $stmt->get_result()){
    //originally I used wrong method below
    while($row = $result->fetch_assoc()) {
            $myArray[] = $row;
    }
    //uncomment below if you're sending response as json responese
    //header('Content-Type: application/json');
    echo json_encode($myArray);
}

$result->close();