三表条件查询-php-mysql
我有三张桌子 使用者 学校三表条件查询-php-mysql,php,mysql,html-table,Php,Mysql,Html Table,我有三张桌子 使用者 学校 ________________________________________________________________ |School_ID | School name | school address | school contact info| ---------------------------------------------------------------- 图画 _____________________________________
________________________________________________________________
|School_ID | School name | school address | school contact info|
----------------------------------------------------------------
图画
___________________________________________
| Picture ID | User_ID | School_ID|file path|
-------------------------------------------
根据学校ID,我想显示如下信息
学校名称、学校地址、用户名、用户联系信息以及所有具有匹配学校ID的图片
php中的脚本是什么。
我在这个网站上研究了几天,尝试了很多代码,但到目前为止都没有效果
这是我使用的代码
<?php
$sql="SELECT Schoolname, School_contact_info, email, description, address, website, file, userName FROM school, picture, user WHERE Location_ID=Picture_ID ORDER BY Location_ID desc";
$result_set=mysql_query($sql);
while($row=mysql_fetch_array($result_set))
{
?>
<div href=<?php $row['Location_ID'] ?>>
<td><?php echo $row['Location_ID'] ?></td>
<td><?php echo $row['name2'] ?></td>
<td><?php echo $row['email'] ?></td>
<div><td><?php echo $row['description'] ?></td></div>
</div>
<div><img src="uploads/<?php echo $row['file'];?>" alt=" " height="75" width="75"></div>
<br>
<?php
}
?>
“alt=”“height=“75”width=“75”>
我想显示学校信息,以及所有以学校ID作为外键的图片。查询应使用
select school_name,school_address,user_name,user_contact_information
from user,school,picture where user.user_id=picture_id
and school.school_id=picture.picture_id
<?php
$con=mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Perform queries
mysqli_query($con,"select school_name,school_address,user_name,user_contact_information
from user,school,picture where user.user_id=picture_id
and school.school_id=picture.picture_id");
选择学校名称、学校地址、用户名、用户联系信息
来自用户、学校、用户所在的图片。用户\u id=图片\u id
还有学校。学校id=picture.picture\u id
在表结构中,没有提供查询中使用的所有列详细信息。
但是试试这个:
SELECT s.Schoolname, s.School_contact_info, s.email, s.description, s.address, s.website,
p.file, u.userName
FROM school as s,
picture as p on s.School_ID=p.School_ID,
user as u on p.User_ID=u.User_ID
WHERE s.Location_ID=p.Picture_ID ORDER BY s.Location_ID desc
我假设像Location\u ID,email,website
这样的栏目都是来自学校的表格。并且尝试了很多代码
…你尝试了什么,你能把它包括进去吗?我想,要求一个完整的PHP脚本和一个查询对于一个问题来说太宽泛了。我同意@TimBiegeleisen,这个问题不会受到欢迎没有演示自己的努力。@TimBiegeleisen我已经用我使用的代码编辑了这个问题。谢谢。
SELECT s.Schoolname, s.School_contact_info, s.email, s.description, s.address, s.website,
p.file, u.userName
FROM school as s,
picture as p on s.School_ID=p.School_ID,
user as u on p.User_ID=u.User_ID
WHERE s.Location_ID=p.Picture_ID ORDER BY s.Location_ID desc