如何在另一个php页面(包括包含GET请求的php页面)上显示超链接的GET输出
home.php如何在另一个php页面(包括包含GET请求的php页面)上显示超链接的GET输出,php,html,Php,Html,home.php <?php include("header.php"); include("session.php"); ?> <h3>Welcome <?php echo $login_session; ?></h3> <?php include("feed.php"); ?> 欢迎 feed.php <?php include("categories.php"); function Qfeed(
<?php
include("header.php");
include("session.php");
?>
<h3>Welcome <?php echo $login_session; ?></h3>
<?php include("feed.php"); ?>
欢迎
feed.php
<?php include("categories.php");
function Qfeed($cat){
//output is echoed here...
}
if(isset($_GET["cat"])) {
$cat = $_GET["cat"];
Qfeed($cat);
}
?>
categories.php
<a href="./feed.php?cat=1"><li class="selected">All categories</li></a>
问题:每次我点击home.php页面上的“allcategories”链接时,输出都显示在feed.php上。我希望它显示在包含feed.php的home.php页面上。因为您正在链接中调用feed.php?cat=1:
<a href="./feed.php?cat=1"><li class="selected">All categories</li></a>
尝试调用home.php
<a href="./home.php?cat=1"><li class="selected">All categories</li></a>
因为您正在链接中调用feed.php?cat=1:
<a href="./feed.php?cat=1"><li class="selected">All categories</li></a>
尝试调用home.php
<a href="./home.php?cat=1"><li class="selected">All categories</li></a>