Php 等效mysqli

我有这个：

$rs = mysql_query('select zip  from _zipcode where zip like "'.$consulta .'%"');

如何将上面的代码转换为mysqli

我尝试过这样的事情，但没有完成

($sql = $db -> prepare('select zip from _zipcode where zip // ));

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所有这些都基于您的线路：

     $rs = mysql_query('select zip  from _zipcode where zip like "'.$consulta .'%"');

SQLi行：

        $query="select zip  from _zipcode where zip like " .$consulta . "%";
        $rs = mysqli_query($connection_information,$query) or  die(mysqli_error($connection_information));
       $row_rs = mysqli_fetch_assoc($rs);
       $totalRows_rs = mysqli_num_rows($rs);

    do {  
        echo $row_rs['zip'];

        } while ($row_rs = mysqli_fetch_assoc($rs));
          $rows = mysqli_num_rows($rs);
          if($rows > 0) {
           mysqli_data_seek($rs, 0);
           $row_rs = mysqli_fetch_assoc($rs);
                          }

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我认为这并不直接等同于。。。我从你写的代码开始。这能回答你的问题吗？使用

die（mysqli_error（$conn））是一个非常糟糕的主意

在您的代码中，因为它可能会泄漏敏感信息。有关更多说明，请参阅本文：

        $query="select zip  from _zipcode where zip like " .$consulta . "%";
        $rs = mysqli_query($connection_information,$query) or  die(mysqli_error($connection_information));
       $row_rs = mysqli_fetch_assoc($rs);
       $totalRows_rs = mysqli_num_rows($rs);

    do {  
        echo $row_rs['zip'];

        } while ($row_rs = mysqli_fetch_assoc($rs));
          $rows = mysqli_num_rows($rs);
          if($rows > 0) {
           mysqli_data_seek($rs, 0);
           $row_rs = mysqli_fetch_assoc($rs);
                          }