无法使用php插入localhost（mysql）数据库

我无法将注册表数据插入本地主机数据库

我正在使用xampp服务器，运行mysql 5、PHP7和apache2。我提供了可以将表单数据插入数据库的代码。数据库已连接。我也重新启动了xampp服务器，但它显示了相同的问题

<?php 

    $active='Account';
    include("includes/header.php");

?>
 //html form with correct name values
<?php 

if(isset($_POST['register'])){

    $c_name = $_POST['c_name'];

    $c_email = $_POST['c_email'];

    $c_pass = $_POST['c_pass'];

    $c_country = $_POST['c_country'];

    $c_city = $_POST['c_city'];

    $c_contact = $_POST['c_contact'];

    $c_address = $_POST['c_address'];

    $c_image = $_FILES['c_image']['name'];

    $c_image_tmp = $_FILES['c_image']['tmp_name'];

    move_uploaded_file($c_image_tmp,"customer/customer_images/$c_image");

    $insert_customer = "insert into customers (customer_name,customer_email,customer_pass,customer_country,customer_city,customer_contact,customer_address,customer_image,customer_ip) values ('$c_name','$c_email','$c_pass','$c_country','$c_city','$c_contact','$c_address','$c_image','$c_ip')";

    $result = mysqli_query($con,$insert_customer);

    $sel_cart = "select * from cart where ip_add='$c_ip'";

    $run_cart = mysqli_query($con,$sel_cart);

    $check_cart = mysqli_num_rows($run_cart);

    if($check_cart>0){

        $_SESSION['customer_email']=$c_email;

        echo "<script>alert('User is already present');</script>";

        echo "<script>window.open('checkout.php','_self')</script>";

    }else{  

        $_SESSION['customer_email']=$c_email;

        echo "<script>alert('You have been Registered Sucessfully')</script>";

        echo "<script>window.open('index.php','_self')</script>";

    }

}

?>

//具有正确名称值的html表单
选中您定义的$con变量。连接变量应该在页面上定义，并使用mysqli函数调用

$result=mysqli\u查询（$con，$insert\u客户）
 您对SQL注入非常开放。由于您使用的是mysqli，请利用和。这将解决可能出现的任何令人讨厌的引用问题。当查询无法按预期工作时，您需要显式检查以找出原因。为什么将此标记为“ajax”？用于此的HTML在哪里？