Php WordPress统计不同自定义帖子类型的用户帖子

我一直在寻找一种方法来计算用户创建的自定义帖子的数量，并且能够使用以下代码段完成此操作：

<?php

    $userid = get_current_user_id();

    function count_user_posts_by_type($userid, $post_type = 'foo_type', $post_status = 'publish') {

    global $wpdb; 
    $query = "SELECT COUNT(*) FROM $wpdb->posts WHERE post_author = $userid AND post_type = '$post_type' AND post_status = '$post_status'"; 
    $count = $wpdb->get_var($query); 
    return apply_filters('get_usernumposts', $count, $userid);

} ?>

---

将第二个post\u类型添加到查询中：

$query = "SELECT COUNT(*) FROM $wpdb->posts WHERE post_author = $userid AND (post_type = '$post_type' OR post_type='$post_type_2') AND post_status = '$post_status'"; 

将第二个post_类型添加到查询：

$query = "SELECT COUNT(*) FROM $wpdb->posts WHERE post_author = $userid AND (post_type = '$post_type' OR post_type='$post_type_2') AND post_status = '$post_status'"; 

尝试下面给出的自定义函数

function my_count_posts_by_user($post_author=null,$post_type=array(),$post_status=array()) {
    global $wpdb;

    if(empty($post_author))
        return 0;

    $post_status = (array) $post_status;
    $post_type = (array) $post_type;

    $sql = $wpdb->prepare( "SELECT COUNT(*) FROM $wpdb->posts WHERE post_author = %d AND ", $post_author );

    //Post status
    if(!empty($post_status)){
        $argtype = array_fill(0, count($post_status), '%s');
        $where = "(post_status=".implode( " OR post_status=", $argtype).') AND ';
        $sql .= $wpdb->prepare($where,$post_status);
    }

    //Post type
    if(!empty($post_type)){
        $argtype = array_fill(0, count($post_type), '%s');
        $where = "(post_type=".implode( " OR post_type=", $argtype).') AND ';
        $sql .= $wpdb->prepare($where,$post_type);
    }

    $sql .='1=1';
    $count = $wpdb->get_var($sql);
    return $count;
} 

然后用以下命令响应结果：

<?php echo count_user_posts_by_type($userid); ?>

<?php echo my_count_posts_by_user($userid , array('posttype1' , 'posttype2')); ?>



请查看下面给出的url


谢谢
尝试下面提供的自定义功能

function my_count_posts_by_user($post_author=null,$post_type=array(),$post_status=array()) {
    global $wpdb;

    if(empty($post_author))
        return 0;

    $post_status = (array) $post_status;
    $post_type = (array) $post_type;

    $sql = $wpdb->prepare( "SELECT COUNT(*) FROM $wpdb->posts WHERE post_author = %d AND ", $post_author );

    //Post status
    if(!empty($post_status)){
        $argtype = array_fill(0, count($post_status), '%s');
        $where = "(post_status=".implode( " OR post_status=", $argtype).') AND ';
        $sql .= $wpdb->prepare($where,$post_status);
    }

    //Post type
    if(!empty($post_type)){
        $argtype = array_fill(0, count($post_type), '%s');
        $where = "(post_type=".implode( " OR post_type=", $argtype).') AND ';
        $sql .= $wpdb->prepare($where,$post_type);
    }

    $sql .='1=1';
    $count = $wpdb->get_var($sql);
    return $count;
} 

然后用以下命令响应结果：

<?php echo count_user_posts_by_type($userid); ?>

<?php echo my_count_posts_by_user($userid , array('posttype1' , 'posttype2')); ?>



请查看下面给出的url


谢谢

您可以在$args中传递任何支持query\u posts的参数

您可以在$args中传递任何参数，这些参数支持查询文章
简短、简单且有效。我最终使用了这个基于SQL的解决方案，而不是修改我的自定义函数，尽管两者都可以完成这项工作。简短、简单、有效。我最终使用了这个基于SQL的解决方案，而不是修改我的自定义函数，尽管两者都可以完成这项工作。