Php 将查询结果保存到会话数组时显示的数据不正确

Php 将查询结果保存到会话数组时显示的数据不正确,php,html,mysql,Php,Html,Mysql,我设置了以下php页面来查询数据库并将结果保存到会话变量数组中: <?php include 'newCustomer.php'; connect('final'); $query = $_POST['searchDB']; $query = htmlspecialchars($query); // stop HTML characters $query = mysql_real_escape_string($query); //stop SQL inject

我设置了以下php页面来查询数据库并将结果保存到会话变量数组中:

<?php
include 'newCustomer.php';
connect('final');


    $query = $_POST['searchDB']; 
    $query = htmlspecialchars($query); // stop HTML characters
    $query = mysql_real_escape_string($query); //stop SQL injection
    $data = mysql_query("SELECT * FROM customer WHERE First_Name LIKE '$query'") ;//query the DB with search field in colleumn selected//


    if($data === FALSE) {
    $error = 'Query error:'.mysql_error();
    echo $error;
    }
    else
    {
    $test = array();
    $colNames = array();
    while($results = mysql_fetch_assoc($data)){// puts data from database into array, loops until no more

    $test[] = $results;

        }
         $anymatches=mysql_num_rows($data); //checks if the querys returned any results
        if ($anymatches != 0) {
        $_SESSION['names']=$test;

    $colNames = array_keys(reset($test));


    }

            if ($anymatches == 0) 
                    { 
                        echo "Sorry, but we can not find an entry to match your query<br><br>"; 
                    } 

    } 
?>

在输出循环中,尝试用“用户名”替换希望显示的字段名称

foreach($array1 as $name){
    echo'<option value="'.$name["username"].'">'.$name["username"].'</option>';
}
foreach($array1作为$name){
回显'.$name[“username”].';
}

问题在于,您正在将每个
$test
项设置为完整的
$results
数组,而不仅仅是结果数组中的预期列值

你的问题是这条线

$test[] = $results;
换成

$test[] = $results["First_Name"];

然后一切都应该按计划进行。

您还没有开始从主页顶部开始的会话,包括newCustomer。
$test[] = $results["First_Name"];