Php 当我在循环中添加一个额外字段时,循环不起作用

Php 当我在循环中添加一个额外字段时,循环不起作用,php,mysql,mysqli,Php,Mysql,Mysqli,我有以下代码: while ( $qrystmt->fetch() ) { // data array $dataArray[$dbCourseId]['CourseName'] = $dbCourseName; $dataArray[$dbCourseId]['Modules'][$dbModuleId]['ModuleName'] = $dbModuleName; // session data

我有以下代码:

 while ( $qrystmt->fetch() ) { 
          // data array
          $dataArray[$dbCourseId]['CourseName'] = $dbCourseName; 
          $dataArray[$dbCourseId]['Modules'][$dbModuleId]['ModuleName'] = $dbModuleName; 
           // session data
          $_SESSION['idcourse'] = $dbCourseNo;
          $_SESSION['namecourse'] = $dbCourseName;

    }
现在,当我尝试在while循环中显示2个字段时,上面的代码工作正常。但是,当我尝试在while循环中添加第三个字段时,它似乎不起作用,它会给我一个错误,说明undefined
ModuleName

是不是我的布局方式导致了下面while循环中的错误:

while ( $qrystmt->fetch() ) { 
          // data array
          $dataArray[$dbCourseId]['CourseName'] = $dbCourseName; 
          $dataArray[$dbCourseId]['Modules'][$dbModuleId]['ModuleNo'] = $dbModuleNo ['ModuleName'] = $dbModuleName; 
           // session data
          $_SESSION['idcourse'] = $dbCourseNo;
          $_SESSION['namecourse'] = $dbCourseName;

    }
完整代码如下所示,从数据库中选择课程,然后选择与所选课程对应的模块:

 $sql = "SELECT CourseId, CourseNo, CourseName FROM Course"; 

 $sqlstmt=$mysqli->prepare($sql);

 $sqlstmt->execute(); 

 $sqlstmt->bind_result($dbCourseId, $dbCourseNo, $dbCourseName);

 $courses = array(); // easier if you don't use generic names for data 

 $courseHTML = "";  
 $courseHTML .= '<select name="courses" id="coursesDrop">'.PHP_EOL; 
 $courseHTML .= '<option value="">Please Select</option>'.PHP_EOL;  

 while($sqlstmt->fetch()) 
 {   
     $courseid = $dbCourseId;
     $course = $dbCourseNo;
     $coursename = $dbCourseName; 
     $courseHTML .= "<option value='".$courseid."'>" . $course . " - " . $coursename . "</option>".PHP_EOL;  
  } 

  $courseHTML .= '</select>'; 

    ?>

        <?php
if (isset($_POST['submit'])) {

$submittedCourseId = $_POST['courses'];

    $query = "
                 SELECT cm.CourseId, cm.ModuleId, c.CourseNo, m.ModuleNo,
                 c.CourseName,
                 m.ModuleName
                 FROM Course c
                 INNER JOIN Course_Module cm ON c.CourseId = cm.CourseId
                 JOIN Module m ON cm.ModuleId = m.ModuleId
                 WHERE
                 (c.CourseId = ?)
                 ORDER BY c.CourseName, m.ModuleId
                ";

    $qrystmt=$mysqli->prepare($query);
    // You only need to call bind_param once
    $qrystmt->bind_param("s",$submittedCourseId);
    // get result and assign variables (prefix with db)

    $qrystmt->execute(); 

    $qrystmt->bind_result($dbCourseId,$dbModuleId,$dbCourseNo,$dbModuleNo, $dbCourseName,$dbModuleName);

     $qrystmt->store_result();

    $num = $qrystmt->num_rows();

    if($num ==0){
        echo "<p style='color: red'>Please Select a Course</p>";
    } else { 

        $dataArray = array();

 while ( $qrystmt->fetch() ) { 
          // data array
          $dataArray[$dbCourseId]['CourseName'] = $dbCourseName; 
          $dataArray[$dbCourseId]['Modules'][$dbModuleId]['ModuleName'] = $dbModuleName; 
           // session data
          $_SESSION['idcourse'] = $dbCourseNo;
          $_SESSION['namecourse'] = $dbCourseName;

    }

     foreach ($dataArray as $foundCourse => $courseData) {

          $output = ""; 

          $output .= "<p><strong>Course:</strong> " . $foundCourse .  " - "  . $courseData['CourseName'] . "</p>";

       $moduleHTML = ""; 
       $moduleHTML .= '<select name="module" id="modulesDrop">'.PHP_EOL;
       $moduleHTML .= '<option value="">Please Select</option>'.PHP_EOL;      
            foreach ($courseData['Modules'] as $moduleId => $moduleData) {        

            $moduleHTML .= "<option value='$moduleId'>" . $moduleId . " - " . $moduleData['ModuleName'] ."</option>".PHP_EOL;        
  } 
            }
            $moduleHTML .= '</select>';

      echo $output;

      ...
$sql=“从课程中选择CourseId、CourseNo、CourseName”;
$sqlstmt=$mysqli->prepare($sql);
$sqlstmt->execute();
$sqlstmt->bind_result($dbCourseId、$dbCourseNo、$dbCourseName);
$courses=array();//如果数据不使用通用名称,则更容易
$courseHTML=“”;
$courseHTML.=''.PHP\u EOL;
$courseHTML.='请选择'.PHP\u EOL;
而($sqlstmt->fetch())
{   
$courseid=$dbCourseId;
$course=$dbCourseNo;
$coursename=$dbCourseName;
$courseHTML.=''.$course.-''$coursename.''.PHP\u EOL;
} 
$courseHTML.='';
?>

您是否尝试在循环之前使用数组值的回音测试数组? 可能您正试图将一个值赋给一个未定义好的变量。

当您调用

$qrystmt->bind_result($dbCourseId,$dbModuleId,$dbCourseNo,$dbModuleNo, $dbCourseName,$dbModuleName);
您正在将一行分配给$dbModuleNo。所以它可能是一个值,而不是一个数组。这会在您呼叫时引起问题:

$dataArray[$dbCourseId]['Modules'][$dbModuleId]['ModuleNo'] = $dbModuleNo ['ModuleName'] = $dbModuleName; 

$dbModuleNo(可能)没有为'ModuleName'定义。

看起来您从未将$dbModuleNo定义为数组。在循环之前添加$dbModuleNo=array()。

并且
$dbModuleNo['ModuleName']
真的定义了吗?我正在尝试将$dbModuleNo链接到['ModuleNo'],这是数据库中字段的名称